/*题意:给你一个序列经过最小变换,变换一次为一个数+1,一个数-1,使得最大值与最小值相差1:思路:与最后得到的序列相差的sum/2:*/#include<iostream> #include<cstdio> #include<cmath> #include<string> #include<queue> #include<algorithm> #include<stack> #include<cstring>…
C. Load Balancing 题目连接: http://www.codeforces.com/contest/609/problem/C Description In the school computer room there are n servers which are responsible for processing several computing tasks. You know the number of scheduled tasks for each server:…
C. Load Balancing time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output In the school computer room there are n servers which are responsible for processing several computing tasks. You know the…
看到这题是我的想法就是肯定跟平均值有关但是接下来就不知道怎么做了 看完大神的正解数之后,原来发现是这么简单,但是就是不知道为啥一定是平均值和平均值加1,而不是平均值和平均值减1: 好啦下面就贴出大神的代码吧: #include<iostream> #include<cstdio> #include<algorithm> using namespace std; int a[100005]; int main() { int n;scanf("%d",…
C. Load Balancing time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output In the school computer room there are n servers which are responsible for processing several computing tasks. You know the…
C. Load Balancing time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output In the school computer room there are n servers which are responsible for processing several computing tasks. You know the…
Load Balancing Time Limit: 2000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u Submit Status Description In the school computer room there are n servers which are responsible for processing several computing tasks. You know the number of…
How To Use HAProxy to Set Up MySQL Load Balancing Dec  2, 2013 MySQL, Scaling, Server Optimization Ubuntu, Debian         Prelude HAProxy is an open source software which can load balance HTTP and TCP servers. In the previous article on HAProxy we co…
Load Balancing Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=83008#problem/H Description The infamous University of Kala Jadu (UKJ) have been operating underground for the last fourteen centuries t…
Load Balancing 给出每个学生的学分.   将学生按学分分成四组,使得sigma (sumi-n/4)最小.         算法:   折半枚举 #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <string> #include <vector> #i…