A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4383    Accepted Submission(s): 1573 Problem Description Jimmy experiences a lot of stress at work these days, especiall…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5679    Accepted Submission(s): 2086 Problem Description Jimmy experiences a lot of stress at work these days, especiall…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10172    Accepted Submission(s): 3701 Problem Description Jimmy experiences a lot of stress at work these days, especial…

题目链接 题意 :办公室编号为1,家编号为2,问从办公室到家有多少条路径,当然路径要短,从A走到B的条件是,A到家比B到家要远,所以可以从A走向B . 思路 : 先以终点为起点求最短路,然后记忆化搜索. #include <cstdio> #include <queue> #include <cstring> #include <iostream> << ; using namespace std ; int N,M ; ][] ,pre[],d…

题意:看样子很多人都把这题目看错了,以为是求最短路的条数.真正的意思是:假设 A和B 是相连的,当前在 A 处, 如果 A 到终点的最短距离大于 B 到终点的最短距离,则可以从 A 通往 B 处,问满足这种的条件的从办公室到家的路径条数. 分析:1.以终点 2 为起点 Dijkstra跑一边最短路,找到所有点到2的最短距离:        2.直接DFS记忆化搜索. 注意:记忆化搜索时的return值,否则此很容易TLE 解法1:O(n^2) #include<iostream> #inclu…

题目链接:acm.hdu.edu.cn/showproblem.php?pid=1142 Problem Description Jimmy experiences a lot of stress at work these days, especially since his accident made working difficult. To relax after a hard day, he likes to walk home. To make things even nicer,…

Walk I used to think I could be anything, but now I know that I couldn't do anything. So I started traveling. The nation looks like a connected bidirectional graph, and I am randomly walking on it. It means when I am at node i, I will travel to an ad…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=1078 题意:给出n*n的格子,每个各自里面有些食物,问一只老鼠每次走最多k步所能吃到的最多的食物 一道简单的记忆化搜索题,从起点开始搜索即可没什么问题,可以拿来练练手. #include <iostream> #include <cstring> #include <algorithm> #include <cstdio> using namespace std…

思路:状态最多有2^12,采用记忆化搜索!! 代码如下: #include<iostream> #include<stdio.h> #include<algorithm> #include<iomanip> #include<cmath> #include<cstring> #include<vector> #define inf 1<<30 using namespace std; ]={{,},{,},{,…

pid=1078">FatMouse and Cheese Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4811    Accepted Submission(s): 1945 Problem Description FatMouse has stored some cheese in a city. The city can…

Play Game Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 24    Accepted Submission(s): 18 Problem Description Alice and Bob are playing a game. There are two piles of cards. There are N cards i…

题意  中文 最基础的数位DP  这题好像也能够直接暴力来做   令dp[i][j]表示以 j 开头的 i 位数有多少个满足条件 那么非常easy有状态转移方程 dp[i][j] = sum{ dp[i-1][k] }, k = 0...9, j != 4 && !( j == 6 && k == 2)  最后统计个数即可了 #include <bits/stdc++.h> using namespace std; int dp[8][10]; int dfs(…

寒冰王座 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13001    Accepted Submission(s): 6620 Problem Description 不死族的巫妖王发工资拉,死亡骑士拿到一张N元的钞票(记住,仅仅有一张钞票),为了防止自己在战斗中频繁的死掉,他决定给自己买一些道具,于是他来到了地精商店前. 死亡骑…

Pieces Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1811    Accepted Submission(s): 932 Problem Description You heart broke into pieces.My string broke into pieces.But you will recover one…

题目描述: 策策同学特别喜欢逛公园.公园可以看成一张N个点MM条边构成的有向图,且没有 自环和重边.其中1号点是公园的入口,N号点是公园的出口,每条边有一个非负权值, 代表策策经过这条边所要花的时间. 策策每天都会去逛公园,他总是从1号点进去,从N号点出来. 策策喜欢新鲜的事物,它不希望有两天逛公园的路线完全一样,同时策策还是一个 特别热爱学习的好孩子,它不希望每天在逛公园这件事上花费太多的时间.如果1号点 到N号点的最短路长为d,那么策策只会喜欢长度不超过d + K的路线. 策策同学想知道总共…

A Walk Through the Forest 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1142 Description Jimmy experiences a lot of stress at work these days, especially since his accident made working difficult. To relax after a hard day, he likes to walk home. T…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5306    Accepted Submission(s): 1939 Problem Description Jimmy experiences a lot of stress at work these days, especiall…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8850    Accepted Submission(s): 3267 Problem Description Jimmy experiences a lot of stress at work these days, especiall…

题意: 给你一个图,找最短路.但是有个非一般的的条件:如果a,b之间有路,且你选择要走这条路,那么必须保证a到终点的所有路都小于b到终点的一条路.问满足这样的路径条数 有多少,噶呜~~题意是搜了解题报告才明白的Orz....英语渣~ 思路: 1.1为起点,2为终点,因为要走ab路时,必须保证那个条件,所以从终点开始使用单源最短路Dijkstra算法,得到每个点到终点的最短路,保存在dis[]数组中. 2.然后从起点开始深搜每条路,看看满足题意的路径有多少条. 3.这样搜索之后,dp[1]就是从起…

原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1142 题目大意:Jimmy要从办公室走路回家,办公室在森林的一侧,家在另一侧,他每天要采取不一样的路线回家.由于他要尽快回家,他在选择路线的时候总是要越来越靠近他家.计算符合条件的路线一共有几种. 解题思路:题目要求“路线要越来越靠近家”,也就是说每次选择下一个结点的时候距离家的距离比当前的结点近.首先该结点离家的距离就是该节点到家的最短路径的长度.所以我们先求出所有节点到家的最短路径.(Dijks…

http://acm.hdu.edu.cn/showproblem.php?pid=1142 这道题是spfa求最短路,然后dfs()求路径数. #include <cstdio> #include <queue> #include <cstring> #include <algorithm> #define maxn 1001 using namespace std; <<; int g[maxn][maxn]; int dis[maxn];…

看到范围基本可以想到dp了,处理起来有点麻烦 #include<iostream> #include<cstdio> #include<cstring> #include<string> #include<algorithm> #include<map> #include<queue> #include<stack> #include<cmath> #include<vector> #d…

S - How many ways Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description 这是一个简单的生存游戏,你控制一个机器人从一个棋盘的起始点(1,1)走到棋盘的终点(n,m).游戏的规则描述如下: 1.机器人一开始在棋盘的起始点并有起始点所标有的能量. 2.机器人只能向右或者向下走,并且每走一步消耗一单位能量. 3.机器人不能在原地停留.…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7330    Accepted Submission(s): 2687 Problem Description Jimmy experiences a lot of stress at work these days, especiall…

Problem    UVA - 10917 - Walk Through the Forest Time Limit: 3000 mSec Problem Description Jimmy experiences a lot of stress at work these days, especially since his accident made working difficult. To relax after a hard day, he likes to walk home. To…

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=4444 题意:给你一些n个矩形,给你一个起点,一个终点,要你求从起点到终点最少需要转多少个弯 题解:因为矩形数量很少50个,可以离散化成102*102的坐标,但是人可以贴着墙壁走,但不能穿过墙壁 所以每个点要分成9等分.建筑物的边占1/3,但是这样有漏洞. 1.当两个墙壁贴在一起,中间还可以过,所以要填补中间 2.当两个矩形的角重合,中间也可以过,要填补中间,但是只能填补中间一个点,不能填补全部的9个…

Tunnels Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 844    Accepted Submission(s): 249 Problem Description Bob is travelling in Xi’an. He finds many secret tunnels beneath the city. In his…

免费馅饼 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 42379    Accepted Submission(s): 14589 Problem Description 都说天上不会掉馅饼,但有一天gameboy正走在回家的小径上,忽然天上掉下大把大把的馅饼.说来gameboy的人品实在是太好了,这馅饼别处都不掉,就掉落在他身旁的…

漫步校园 http://acm.hdu.edu.cn/showproblem.php?pid=1428 Problem Description LL最近沉迷于AC不能自拔,每天寝室.机房两点一线.由于长时间坐在电脑边,缺乏运动.他决定充分利用每次从寝室到机房的时间,在校园里散散步.整个HDU校园呈方形布局,可划分为n*n个小方格,代表各个区域.例如LL居住的18号宿舍位于校园的西北角,即方格(1,1)代表的地方,而机房所在的第三实验楼处于东南端的(n,n).因有多条路线可以选择,LL希望每次的散…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1428 漫步校园 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description LL最近沉迷于AC不能自拔,每天寝室.机房两点一线.由于长时间坐在电脑边,缺乏运动.他决定充分利用每次从寝室到机房的时间,在校园里散散步.整个HDU校园呈方形布局,可划分为n*n…