Dwarves （有向图判环）

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Dwarves （有向图判环）

Dwarves 时间限制: 1 Sec 内存限制: 64 MB提交: 14 解决: 4[提交][状态][讨论版] 题目描述 Once upon a time, there arose a huge discussion among the dwarves in Dwarﬂand. The government wanted to introduce an identity card for all inhabitants. Most dwarves accept to be small, b…

COJ 3012 LZJ的问题（有向图判环）

传送门:http://oj.cnuschool.org.cn/oj/home/problem.htm?problemID=1042 试题描述: LZJ有一个问题想问问大家.他在写函数时有时候很头疼,如他写了这样几个函数: void f1(){ f2(); f3();}void f2(){ f3();}void f3(){ f1();}LZJ发现他无论怎么调换函数的位置,编译器总是不能通过编译,因为编译器规定调用的函数必须在当前函数之前写.还有一种情况是这样的:void f4(){…

HDU 3342 Legal or Not（有向图判环拓扑排序）

Legal or Not Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11382 Accepted Submission(s): 5346 Problem Description ACM-DIY is a large QQ group where many excellent acmers get together. It is…

HDU 5154 Harry and Magical Computer 有向图判环

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5154 题解: 有向图判环. 1.用dfs,正在访问的节点标记为-1,已经访问过的节点标记为1,没有访问过的节点标记为0,如果访问到-1的节点说明说有环. #include<iostream> #include<cstdio> #include<cstring> #include<cmath> using namespace std; typedef long…

CodeForces 937D 936B Sleepy Game 有向图判环,拆点,DFS

题意: 一种游戏,2个人轮流控制棋子在一块有向图上移动,每次移动一条边,不能移动的人为输,无限循环则为平局,棋子初始位置为$S$ 现在有一个人可以同时控制两个玩家,问是否能使得第一个人必胜,并输出一个解,否则判断是否能平局题解: 看到这个题首先我想到了强连通分量,但是事实证明求出强连通分量,缩点对解决问题没有什么帮助.... 能写一些看似正确的算法,但其实是假算法来的.. ........... 所以应该先分析策略,肯定是能赢就赢,不能赢就求平局,最后才算输平局很好判断,有向图上,从$S$点…

POJ 1094 Sorting It All Out（拓扑排序+判环+拓扑路径唯一性确定）

Sorting It All Out Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 39602 Accepted: 13944 Description An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements from s…

Codeforces Round #460 (Div. 2): D. Substring（DAG+DP+判环）

D. Substring time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output You are given a graph with n nodes and m directed edges. One lowercase letter is assigned to each node. We define a path's valu…