题目传送门 Hard problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1066    Accepted Submission(s): 622 Problem Description cjj is fun with math problem. One day he found a Olympic Mathematics pr…

链接 画图推公式 这两种情况 都可用一种公式算出来 就是两圆都求出圆心角 求出扇形的面积减掉三角形面积 #include <iostream> using namespace std; #include<cmath> #include<iomanip> #include<algorithm> int main() { double d,t,t1,s,x,y,xx,yy,r,rr; while(cin>>x>>y>>r) {…

题目大意是:先给你一些圆,你可以任选这些圆中的一个圆点作圆,这个圆的要求是:你画完以后.这个圆要可以覆盖之前给出的每一个圆一半以上的面积,即覆盖1/2以上每一个圆的面积. 比如例子数据,选左边还是选右边没差别,红色的圆为答案(选了左边的圆点),它覆盖了左边圆的1/2以上,也覆盖了右边圆的1/2以上. 知道了怎样求两圆面积交.那么这道题就简单了.仅仅要二分答案,然后枚举每个圆点,假设全都覆盖了1/2以上就继续二分,最后答案就得出来了. #include<iostream> #include<…

Circular Area Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5682   Accepted: 2225 Description Your task is to write a program, which, given two circles, calculates the area of their intersection with the accuracy of three digits after…

题目链接: POJ:http://poj.org/problem? id=2546 ZOJ:problemId=597" target="_blank">http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=597 Description Your task is to write a program, which, given two circles, calculates the area of the…

转载 两圆相交分如下集中情况:相离.相切.相交.包含. 设两圆圆心分别是O1和O2,半径分别是r1和r2,设d为两圆心距离.又因为两圆有大有小,我们设较小的圆是O1. 相离相切的面积为零,代码如下: double d = sqrt((a.x-b.x)*(a.x-b.x) + (a.y-b.y)*(a.y-b.y)); if (d >= r1+r2) return 0; double d = sqrt((a.x-b.x)*(a.x-b.x) + (a.y-b.y)*(a.y-b.y)); if (…

还没开始写题解我就已经内牛满面了,从晚饭搞到现在,WA得我都快哭了呢 题意: 在DotA中,你现在1V5,但是你的英雄有一个半径为r的眩晕技能,已知敌方五个英雄的坐标,问能否将该技能投放到一个合适的位置,使得对面所有敌人都被眩晕,这样你就有机会能够逃脱. 分析: 对于敌方一个英雄来说,如果技能的投放位置距离他不超过r则满足要求,那么如果要眩晕所有的敌人,可行区域就是以五人为中心的半径为r的圆的相交区域. 现在问题就转化为求五个半径相同的圆的相交部分的面积,如果只有一个点则输出该点. 在求交之前,…

Description The city of M is a famous shopping city and its open-air shopping malls are extremely attractive. During the tourist seasons, thousands of people crowded into these shopping malls and enjoy the vary-different shopping. Unfortunately, the…

Open-air shopping malls Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2458    Accepted Submission(s): 906 Problem Description The city of M is a famous shopping city and its open-air shopping…

已知两圆圆心坐标和半径,求相交部分面积: #include <iostream> using namespace std; #include<cmath> #include<stdio.h> #define PI 3.141593 struct point//点 { double x,y; }; struct circle//圆 { point center; double r; }; float dist(point a,point b)//求圆心距 { return…