Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 20687   Accepted: 8004 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled…

Dungeon Master  Descriptions: You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled with rock. It takes one minute to move one unit north, south, east, west, up or…

BUPT2017 wintertraining(16) #5 B POJ - 2251 题意 3维的地图,求从S到E的最短路径长度 题解 bfs 代码 #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #define N 35 using namespace std; struct node{ int x,y,z,d; }s,e; int L,R,C; int…

若不会广搜转向[广搜] [题目描述] 这题是一个三维的迷宫题目,其中用‘.’表示空地,‘#’表示障碍物,‘S’表示起点,‘E’表示终点,求从起点到终点的最小移动次数,解法和二维的类似,只是在行动时除了东南西北移动外还多了上下.可以上下左右前后移动,每次都只能移到相邻的空位,每次需要花费一分钟,求从起点到终点最少要多久. [输入] 多组测试数据. 一组测试测试数据表示一个三维迷宫: 前三个数,分别表示层数.一个面的长和宽,后面是每层的平面图.前三个数据为三个零表示结束. [输出] 最小移动次数.…

对于深度优先算法,第一个直观的想法是只要是要求输出最短情况的详细步骤的题目基本上都要使用深度优先来解决.比较常见的题目类型比如寻路等,可以结合相关的经典算法进行分析. 常用步骤: 第一道题目:Dungeon Master  http://poj.org/problem?id=2251 Input The input consists of a number of dungeons. Each dungeon description starts with a line containing th…

http://poj.org/problem?id=2251 Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18773   Accepted: 7285 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes…

POJ 2251 题目大意: 给出一三维空间的地牢,要求求出由字符'S'到字符'E'的最短路径,移动方向可以是上,下,左,右,前,后,六个方向,每移动一次就耗费一分钟,要求输出最快的走出时间.不同L层的地图,相同RC坐标处是相连通的.(.可走,#为墙) 解题思路:从起点开始分别往6个方向进行BFS(即入队),并记录步数,直至队为空.若一直找不到,则困住. /* POJ 2251 Dungeon Master --- 三维BFS(用BFS求最短路) */ #include <cstdio> #i…

题目链接:http://poj.org/problem?id=2251 Dungeon Master Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 51402   Accepted: 19261 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit…

题目传送门 /* BFS:这题很有意思,像是地下城,图是立体的,可以从上张图到下一张图的对应位置,那么也就是三维搜索,多了z坐标轴 */ #include <cstdio> #include <algorithm> #include <cstring> #include <queue> using namespace std; ; const int INF = 0x3f3f3f3f; struct Point { int x, y, z, step; };…

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