题目 The only difference between the easy and the hard versions is the maximum value of k. You are given an infinite sequence of form "112123123412345…" which consist of blocks of all consecutive positive integers written one after another. The fi…

题目链接 问题分析 奇奇怪怪的题... 首先思路达成一致,从大到小一步一步确定位置. 我们一边分析,一边讲算法. 112123123412345123456123456712345678123456789123456789101234567891011123456789101112 假设我们现在要找的是这个串中的倒数第二个位置(就是1),我们可以这样做: 首先,我们想象着把串分开,变成 1 12 123 1234 12345 123456 1234567 12345678 123456789 1…

http://codeforces.com/problemset/problem/1216/E1 E1. Numerical Sequence (easy version) time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The only difference between the easy and the hard ver…

cf1216E2 Numerical Sequence (hard version) 题目大意 一个无限长的数字序列,其组成为\(1 1 2 1 2 3 1.......1 2 ... n...\),即重复的\(1~1,1~2....1~n\),给你一个k,求第k(k<=1e18)个数字是什么 solution 暴力枚举妥妥T掉 手摸能看出来每一个单独的序列是等差数列 然后每一个序列的数字个数也是等差数列 如果预处理出等差数列的数组,那么询问的时候直接调用即可 参考lzz的blogs 说说这一段…

The only difference between the easy and the hard versions is the maximum value of \(k\). You are given an infinite sequence of form "112123123412345-" which consist of blocks of all consecutive positive integers written one after another. The f…

题目描述 The only difference between the easy and the hard versions is the maximum value of k. You are given an infinite sequence of form "112123123412345--" which consist of blocks of all consecutive positive integers written one after another. The…

题目: 题意: 已知一个序列: 112123123412345123456123456712345678123456789123456789101234567891011... 求这个序列第k个数是多少. 分析: 首先,我们先来看这样一个问题,让求123456789101112131415...一直到n的长度是多少,我们会怎么求呢?显然,我们会分开求:1-9一组,10-99一组,100-999一组...当然组数不会很多,然后组内其实就是一些位数相等的数的位数的和,那么当然用乘法解决,数清项数就好…

题目大意 有一个无限长的数字序列,其组成为1 1 2 1 2 3 1.......1 2 ... n...,即重复的1~1,1~2....1~n,给你一个\(k\),求第\(k(k<=10^{18})\)个数字是什么. 思路 设\(a[i]\)为该数到达\(i\)的长度,\(b[i]\)为第\(i\)个数那一块的长度,\(\sum b[i]=a[i]\),发现\([10^i,10^{i+1})\)的数长度均为\(i+1\),那么在这一段中\(b[i]\)都是一个等差数列,而计算\(a[i]\)就…

EAPOL 协议 一.基本概念 EAPOL 的全称为 Extensible Authentication Protocol Over LAN,即 EAP Over Lan,也即基于局域网的扩展认证协议.EAP是一个普遍使用的认证机制,它常被用于无线网络或点到点的连接中.EAP不仅可以用于无线局域网,而且可以用于有线局域网.EAP是一个认证框架,不是一个特殊的认证机制.EAP提供一些公共的功能,并且允许协商所希望的认证机制.这些机制被叫做EAP方法,现在大约有40种不同的方法. 二.EAP的认证过…

Over the years, I have collected, modified, adapted, adopted or created a number of software packages in FORTRAN. You might be able to use one of these libraries, or a routine or two from a library. The packages are at different levels of completion.…

C - Chocolate Bar 题面 There is a bar of chocolate with a height of H blocks and a width of W blocks. Snuke is dividing this bar into exactly three pieces. He can only cut the bar along borders of blocks, and the shape of each piece must be a rectangle…

  MRIcro tutorial 参考网址:http://www.mccauslandcenter.sc.edu/mricro/mricron/ http://www.cabiatl.com/mricro/mricro/mricro.html This guide gives is a brief description of how you can use MRIcro and SPM to work with patient scans. For the MRIcro manual and…

Lecture notes of Mathematical analysis Preliminary theory Teaching purpose: Mathematical analysis is a watershed between high school and university. Its core is the thought of limit. Before introducing the concept of limit, let's first review the kno…

Chapter2 Numerical sequence and function Cartesian product set If S and T are sets,then the cartesian product set S×T is formed by taking all ordered pairs (p,q) where p∈S and q∈T. Relations,functions Any subject f of the cartesian product S×T is cal…

Let N be a positive integer. There is a numerical sequence of length 3N, a=(a1,a2,…,a3N). Snuke is constructing a new sequence of length 2N, a', by removing exactly N elements from a without changing the order of the remaining elements. Here, the sco…

D - 3N Numbers Time limit : 2sec / Memory limit : 256MB Score : 500 points Problem Statement Let N be a positive integer. There is a numerical sequence of length 3N, a=(a1,a2,…,a3N). Snuke is constructing a new sequence of length 2N, a', by removing…

http://www.intel.com/content/www/us/en/processors/processor-numbers.html About Intel® Processor Numbers The processor number is one of several factors, along with processor brand, specific system configurations, and system-level benchmarks, to be con…

2ed,  by Timothy Sauer DEFINITION 1.3A solution is correct within p decimal places if the error is less than 0.5 × 10$^{−p}$ .-P29Bisection Method的优点是计算次数(step)是确定的(interval<精度).后面介绍的算法的interval是不确定的, 所以什么时候结束计算呢?不知道.所以定义“stopping criteria’’来决定什么时候结束…

http://aria42.com/blog/2014/12/understanding-lbfgs/ Numerical optimization is at the core of much of machine learning. Once you’ve defined your model and have a dataset ready, estimating the parameters of your model typically boils down to minimizing…

2ed,  by Timothy Sauer DEFINITION 1.3A solution is correct within p decimal places if the error is less than 0.5 × 10$^{−p}$ .-P29Bisection Method的优点是计算次数(step)是确定的(interval<精度).后面介绍的算法的interval是不确定的, 所以什么时候结束计算呢?不知道.所以定义“stopping criteria’’来决定什么时候结束…

Numerical Summation of a Series Time Limit: 10 Seconds      Memory Limit: 32768 KB      Special Judge Produce a table of the values of the series Equation 1 for the 2001 values of x, x= 0.000, 0.001, 0.002, ..., 2.000. All entries of the table must h…

Sequence Models This is the fifth and final course of the deep learning specialization at Coursera which is moderated by deeplearning.ai Here are the course summary as its given on the course link: This course will teach you how to build models for n…

第三周 序列模型和注意力机制(Sequence models & Attention mechanism) 基础模型(Basic Models) 在这一周,你将会学习 seq2seq(sequence to sequence)模型,从机器翻译到语音识别,它们都能起到很大的作用,从最基本的模型开始.之后你还会学习集束搜索(Beam search)和注意力模型(Attention Model),一直到最后的音频模型,比如语音. 现在就开始吧,比如你想通过输入一个法语句子,比如这句 "Jane…

About this Course This course will teach you how to build models for natural language, audio, and other sequence data. Thanks to deep learning, sequence algorithms are working far better than just two years ago, and this is enabling numerous exciting…

Lesson 5 Sequence Models 这篇文章其实是 Coursera 上吴恩达老师的深度学习专业课程的第五门课程的课程笔记. 参考了其他人的笔记继续归纳的. 符号定义 假如我们想要建立一个能够自动识别句中人名地名等位置的序列模型,也就是一个命名实体识别问题,这常用于搜索引擎.命名实体识别系统可以用来查找不同类型的文本中的人名.公司名.时间.地点.国家名和货币名等等. 我们输入语句 "Harry Potter and Herminoe Granger invented a new s…

oracle创建序列化: CREATE SEQUENCE seq_itv_collection            INCREMENT BY 1  -- 每次加几个              START WITH 1399       -- 从1开始计数              NOMAXVALUE        -- 不设置最大值              NOCYCLE               -- 一直累加,不循环              CACHE 10; oracle修改序列…

功能:备份存储过程,视图,函数触发器,Sequence序列号等准备工作:--1.创建文件夹 :'E:/OracleBackUp/ProcBack';--文本存放的路径--2.执行:create or replace directory MyProcBakPath as 'E:/OracleBackUp/ProcBack';--3.赋权限:sqlplus /nologconn user/pswd as sysdbagrant select on DBA_OBJECTS to user;--4.创建…

环境:Oracle 11.2.0.4 DG 故障现象: 客户在备库告警日志中发现GAP sequence提示信息: Mon Nov 21 09:53:29 2016 Media Recovery Waiting for thread 1 sequence 12034 Fetching gap sequence in thread 1, gap sequence 12034-12078 Mon Nov 21 09:55:20 2016 FAL[client]: Failed to request…

The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…

Check whether the original sequence org can be uniquely reconstructed from the sequences in seqs. The org sequence is a permutation of the integers from 1 to n, with 1 ≤ n ≤ 104. Reconstruction means building a shortest common supersequence of the se…