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Description On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is played on an ice game board on which a square mesh is marked. They use only a single stone. The…
题目链接. 分析: 本题BFS A不了. 00100 00001 01020 00000 00010 00010 00010 00010 00030 对于这样的数据,本来应当是 5 步,但bfs却 4 步.具体原因可以仔细看一下上面的样例. 应当dfs穷举所有的可能,找出最短的. #include <iostream> #include <cstdio> #include <queue> using namespace std; ; <<); , -, ,…
http://poj.org/problem?id=3009 Description On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is played on an ice game board on which a square mesh is marked. The…
Curling 2.0 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 14563   Accepted: 6080 Description On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is…
Curling 2.0 Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11879   Accepted: 5028 Description On Planet MM-21, after their Olympic games this year, curling is getting popular. But the rules are somewhat different from ours. The game is…
POJ3009-Curling 2.0 题意: 要求把一个冰壶从起点“2”用最少的步数移动到终点“3” 其中0为移动区域,1为石头区域,冰壶一旦想着某个方向运动就不会停止,也不会改变方向(想想冰壶在冰上滑动),除非冰壶撞到石头1 或者 到达终点 3 如果能在10步以内到达终点,输出到达终点所需的步数,否则输出-1 注意的是: 冰壶撞到石头后,冰壶会停在石头前面,此时(静止状态)才允许改变冰壶的运动方向,而该块石头会破裂,石头所在的区域由1变为0. 也就是说,冰壶撞到石头后,并不会取代石头的位置.…
https://vjudge.net/problem/POJ-3009 做完这道题,感觉自己对dfs的理解应该又深刻了. 1.一般来说最小步数都用bfs求,但是这题因为状态记录很麻烦,所以可以用dfs. 2.在用dfs的时候,mp时一个全局变量,对于平等的走法,每一个走法结束后一定要状态复原!!!(也就是代码36-38行)否则会对其他走法产生影响. #include<iostream> #include<cstdio> #include<queue> #include&…
Curling 2.0 Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 30   Accepted Submission(s) : 16 Problem Description On Planet MM-21, after their Olympic games this year, curling is getting popular.…
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