Leetcode 69. Sqrt(x) Easy https://leetcode.com/problems/sqrtx/ Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncat…
69. Sqrt(x) Total Accepted: 93296 Total Submissions: 368340 Difficulty: Medium 提交网址: https://leetcode.com/problems/sqrtx/ Implement int sqrt(int x). Compute and return the square root of x. 分析: 解法1:牛顿迭代法(牛顿切线法) Newton's Method(牛顿切线法)是由艾萨克·牛顿在<流数法>(M…
Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…
Implement int sqrt(int x). Compute and return the square root of x. x is guaranteed to be a non-negative integer. Example 1: Input: 4 Output: 2 Example 2: Input: 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since we want to return…
Implement int sqrt(int x). 思路: Binary Search class Solution(object): def mySqrt(self, x): """ :type x: int :rtype: int """ l = 0 r = x while l <= r: mid = (l+r)//2 if mid*mid < x: l = mid + 1 elif mid*mid > x: r = mi…
Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…
Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…
可怕的同时考数值溢出和二分的酱油题之一,常在各种小公司的笔试中充当大题来给你好看... 题意很简单,在<二分查找综述>中有描述. 重点:使用简单粗暴的long long来避免溢出,二分均方根的答案来得到准确解. 当然这里的溢出不止是相乘的溢出,还有第六行那段代码的溢出,每次都会有几个解决问题的斗士牺牲在这里... class Solution { public: int mySqrt(int x) { , b = x; while(a <= b ){ ; if(mid * mid ==…
原文作者:aircraft 原文链接:https://www.cnblogs.com/DOMLX/p/10940636.html 唉!最近忙着面试找实习,然后都是面试的很多是leetcode的算法题,所以自己就刷了一遍,并且做些笔记,以后再来复习好了,悲催的大学生..... 一.从(排序!)数组中删除重复项 给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成.…
本文实例讲述了jQuery实现form表单基于ajax无刷新提交方法.分享给大家供大家参考,具体如下: 首先,新建Login.html页面: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.o…