SELECT COUNT(*) FROM [tbiz_PuzzleBasic] SELECT A.BasicID,A.Name,A.Gender,B.WorkID,B.Company,B.Position FROM [tbiz_PuzzleBasic] A LEFT JOIN [tbiz_PuzzleWork] B ON B.BasicID = A.BasicID 读作:A表在B表的左边,A表的中的记录都将返回,A表是主表 FROM [tbiz_PuzzleBasic] A RIGHT JOIN…