Given an array of integers, the majority number is the number that occurs more than half of the size of the array. Find it. Notice You may assume that the array is non-empty and the majority number always exist in the array. Have you met this questio…

Given an array of integers, the majority number is the number that occurs more than half of the size of the array. Find it. Notice You may assume that the array is non-empty and the majority number always exist in the array. Have you met this questio…

Given an array of integers and a number k, the majority number is the number that occurs more than 1/k of the size of the array. Find it. Have you met this question in a real interview? Yes Example Given [3,1,2,3,2,3,3,4,4,4] and k=3, return 3. Note…

Given an array of integers, the majority number is the number that occurs more than 1/3 of the size of the array. Find it. Have you met this question in a real interview? Yes Example Given [1, 2, 1, 2, 1, 3, 3], return 1. Note There is only one major…

Majority Number II 原题链接: http://lintcode.com/en/problem/majority-number-ii/# Given an array of integers, the majority number is the number that occurs more than 1/3 of the size of the array. Find it. Note There is only one majority number in the arra…

Majority Number 原题链接:http://lintcode.com/en/problem/majority-number/# Given an array of integers, the majority number is the number that occurs more than half of the size of the array. Find it. Example For [1, 1, 1, 1, 2, 2, 2], return 1 Challenge O(…

Given an array of integers, the majority number is the number that occurs more than 1/3 of the size of the array. Find it. Note There is only one majority number in the array Example For [1, 2, 1, 2, 1, 3, 3] return 1 Challenge O(n) time and O(1) spa…

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. Credits:Special thanks to @t…

网址:https://leetcode.com/problems/majority-element/ 参考:https://blog.csdn.net/u014248127/article/details/79230221 可以直接通过map解决 利用神奇的 摩尔投票算法( Boyer-Moore Voting Algorithm) 不断的消去两个不同的数,最后剩下的数肯定是所求的众数! 细节: 若第一个数的出现次数不止 1,则“消去”意味着次数-1 如果两数相同,要将此数的次数累加 class…

给定一个大小为 n 的数组,找到其中的众数.众数是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素.你可以假设数组是非空的,并且数组中的众数永远存在. 详见:https://leetcode.com/problems/majority-element/description/ Java实现: 方法一: class Solution { public int majorityElement(int[] nums) { int n=nums.length; if(n==0||nums==null){…