POJ 3461 Oulipo(字符串hash)】的更多相关文章

POJ 3461 Oulipo(乌力波) Time Limit: 1000MS   Memory Limit: 65536K [Description] [题目描述] The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: Tou…
HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP) Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: Tout avait…
Oulipo Problem's Link ---------------------------------------------------------------------------- Mean: 给你一个模式串P和一个母串S,让你统计P串在S串中出现的次数. analyse: 一开始想到的就是使用KMP,就用KMP写了,93ms,挺快的. 我又用AC自动机写了一遍,万万没想到竟然超时了. 后来看别人有用字符串hash写的,于是又用字符串hash写了一遍,代码30+行,而且速度也挺快…
题目链接 字符串hash判断字符串是否相等. code #include<cstdio> #include<algorithm> #include<cstring> using namespace std; typedef unsigned long long uLL; ; uLL f[]; uLL Hash[]; ],b[]; int main () { int T; scanf("%d",&T); f[] = ; ; i<=; ++…
  E - Oulipo Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 3461 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a memb…
[题意] 给一个字符串组成的矩阵,规模为n*m(n<=10000,m<=10),如果某两列中存在两行完全相同,则输出NO和两行行号和两列列号,否则输出YES [题解] 因为m很小,所以对每一行枚举其中两个字符串,检查之前行中对应的两列里是否重复即可.但是如何判重. 一开始想的把字符串做成pair然后用map映射为行号,但是TLE. 后来想到用hash判重,可能是因为哈希函数不够好,还是TLE... 总之这道题卡了三个小时,一直TLE. 枚举每一列,对枚举到的那一列从小到大排序,然后找到相邻两个…
  E - Oulipo Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 3461 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a memb…
传送门:http://poj.org/problem?id=3461 Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 50450   Accepted: 20018 Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a…
Andy the smart computer science student was attending an algorithms class when the professor asked the students a simple question, "Can you propose an efficient algorithm to find the length of the largest palindrome in a string?" A string is sai…
题目链接:http://poj.org/problem?id=3461 题意:给你两个字符串word和text,求出word在text中出现的次数 思路:kmp算法的简单应用,遍历一遍text字符串即可,当前匹配的字符数达到word字符串的长度,即可确定word字符串出现一次了. code: #include <cstdio> #include <cstring> using namespace std; ; ; char word[MAXM]; char text[MAXN];…