题目链接:http://www.lightoj.com/volume_showproblem.php?problem=1233 题目就不说明了. 背包的二进制优化,比如10可以表示为1 2 4 3,而这些数能表示1 ~ 10的任意的数.然后类似01背包就好了. #include <algorithm> #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio&g…

C - Coin Change (III) Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%lld & %llu Submit Status Practice LightOJ 1233 Description In a strange shop there are n types of coins of value A1, A2 ... An. C1, C2, ... Cn denote the number of…

题目链接:https://leetcode.com/problems/coin-change/ 322. Coin Change My Submissions Question Total Accepted: 15289 Total Submissions: 62250 Difficulty: Medium You are given coins of different denominations and a total amount of money amount. Write a func…

1138 - Trailing Zeroes (III) problem=1138"> problem=1138&language=english&type=pdf">PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB You task is to find minimal natural number N, so that N! contains exactl…

link:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=615 和完全背包一样的思想. #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #inc…

1138 - Trailing Zeroes (III)   PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB You task is to find minimal natural number N, so that N! contains exactly Q zeroes on the trail in decimal notation. As you know N! = 1*2*...*N.…

1138 - Trailing Zeroes (III) PDF (English) Statistics Forum Time Limit: 2 second(s) Memory Limit: 32 MB You task is to find minimal natural number N, so that N! contains exactly Q zeroes on the trail in decimal notation. As you know N! = 1*2*...*N. F…

题目链接:http://lightoj.com/volume_showproblem.php?problem=1138 题目就是给你一个数表示N!结果后面的0的个数,然后让你求出最小的N. 我们可以知道N!里5(包括5的倍数)的个数比2(包括2的倍数)的个数多,所以1对应5!,2对应10!... 而末尾0的个数与N成正比,1e8对应的N最大是400000015.我用二分查询N对应末尾0的个数,要是计算出来末尾0的个数比给你的数还大就L=mid+1,否则就R=mid. #include <iost…

免费做一样新 1004 - Monkey Banana Problem 号码塔 1005 - Rooks 排列 1013 - Love Calculator LCS变形 dp[i][j][k]对于第一个字符串i 到jLCS为k的方案数 1068 - Investigation 数位dp 能被K整数且各位数字之和也能被K整除的数 dp[i][j][k] 到第i位每位数字之和的余数为j 当前数字余数为k 1079 - Just another Robbery 01背包 全部钱之和为背包体积 不被抓的…

UVA.674 Coin Change (DP) 题意分析 有5种硬币, 面值分别为1.5.10.25.50,现在给出金额,问可以用多少种方式组成该面值. 每种硬币的数量是无限的.典型完全背包. 状态转移方程 dp[j+c[i]] = dp[j] + dp[j+c[i]] 代码总览 /* Title:UVA.674 Author:pengwill Date:2017-2-16 */ #include <iostream> #include <cstdio> #include <…