198.HouseRobber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected a…

// // Created by Administrator on 2021/7/27. // #ifndef C__TEST01_HOUSEROBBER_HPP #define C__TEST01_HOUSEROBBER_HPP #include <iostream> #include <vector> using namespace std; class HouseRobber { /* 有一排N栋房子(0 - N-1),房子i里有A[i]个金币 * 一个窃贼想选择一些房子偷金…

#include <malloc.h> int MAX(int x,int y){ return x>y?x:y;} int rob(int* nums, int numsSize) { int *m; int i; m = (int *)malloc(sizeof(int)*(numsSize+1)); m[0] = 0; m[1] = nums[0]; m[2] =MAX(nums[0],nums[1]); for(i=3;i<=numsSize;i++){ m[i] = MA…

House Robber I You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected an…

// // Created by Administrator on 2021/7/27. // #ifndef C__TEST01_HOUSEROBBER2_HPP #define C__TEST01_HOUSEROBBER2_HPP #include <iostream> #include <vector> using namespace std; class HouseRobber2 { /* 有一 圈 N栋房子(0 - N-1),房子i里有A[i]个金币 * 一个窃贼想选择一…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

一直直到bug-free.不能错任何一点. 思路不清晰:刷两天. 做错了,刷一天. 直到bug-free.高亮,标红. 185,OA(YAMAXUN)--- (1) findFirstDuplicate string in a list of string. import java.util.HashSet; import java.util.Set; public class Solution { public static void main(String[] args) { String[…

------------------------------------------------------------第七周:Follow up question 1,寻找峰值 寻找峰值 描述 笔记 数据 评测 你给出一个整数数组(size为n),其具有以下特点: 相邻位置的数字是不同的 A[0] < A[1] 并且 A[n - 2] > A[n - 1] 假定P是峰值的位置则满足A[P] > A[P-1]且A[P] > A[P+1],返回数组中任意一个峰值的位置. 注意事项 数…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

// Ref: https://segmentfault.com/a/1190000003811581// Ref: http://www.cnblogs.com/grandyang/p/4383632.html /*如果选择了抢劫上一个屋子,那么就不能抢劫当前的屋子,所以最大收益就是抢劫上一个屋子的收益如果选择抢劫当前屋子,就不能抢劫上一个屋子,所以最大收益是到上一个屋子的上一个屋子为止的最大收益,加上当前屋子里有的钱*/ public static long houseRobber(int[…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

原题链接在这里:https://leetcode.com/problems/house-robber/ 题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent…

题目 打劫房屋II 在上次打劫完一条街道之后,窃贼又发现了一个新的可以打劫的地方,但这次所有的房子围成了一个圈,这就意味着第一间房子和最后一间房子是挨着的.每个房子都存放着特定金额的钱.你面临的唯一约束条件是:相邻的房子装着相互联系的防盗系统,且 当相邻的两个房子同一天被打劫时,该系统会自动报警. 给定一个非负整数列表,表示每个房子中存放的钱, 算一算,如果今晚去打劫,你最多可以得到多少钱 在不触动报警装置的情况下. 样例 给出nums = [3,6,4], 返回 6, 你不能打劫3和4所在的房…

题目 打劫房屋 假设你是一个专业的窃贼,准备沿着一条街打劫房屋.每个房子都存放着特定金额的钱.你面临的唯一约束条件是:相邻的房子装着相互联系的防盗系统,且 当相邻的两个房子同一天被打劫时,该系统会自动报警. 给定一个非负整数列表,表示每个房子中存放的钱, 算一算,如果今晚去打劫,你最多可以得到多少钱 在不触动报警装置的情况下. 样例 给定 [3, 8, 4], 返回 8. 挑战 O(n) 时间复杂度 且 O(1) 存储. 解题 定义dp[i]表示打劫第i个房间为止所获得的最大收益,而dp[i]的…

题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will a…

213. House Robber II     Total Accepted: 24216 Total Submissions: 80632 Difficulty: Medium Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will…

虽然接触动态规划算法已经有一段时间,给一个01背包问题,能够做到一个表格简单粗暴下去,然后求得结果,但心里总觉得对这个算法理解十分不到位,抱着对算法的热爱,网上很多大牛的算法思维实在让我佩服的五体投地.在此讲一讲动态规划中滚动数组的求解方法,算是对这个知识点做一个记录,也希望有写的不妥的地方,大家能不吝赐教. 首先,我们先看看"滚动数组"的例题,大家可以参考http://www.lintcode.com/en/problem/house-robber/ 题意大概就是说:一个盗贼要去偷盗…

题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will a…

URL : https://leetcode.com/problems/house-robber/ You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent house…

public class Solution { public int Rob(int[] nums) { ; ; ; k < nums.Length; k++) { int tmp = i; i = nums[k] + e; e = Math.Max(tmp, e); } return Math.Max(i, e); } } https://leetcode.com/problems/house-robber/#/description /* 你是一个专业强盗,并计划沿街去盗窃每一个住户.每个房…

House Robber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and …

392-打劫房屋 假设你是一个专业的窃贼,准备沿着一条街打劫房屋.每个房子都存放着特定金额的钱.你面临的唯一约束条件是:相邻的房子装着相互联系的防盗系统,且 当相邻的两个房子同一天被打劫时,该系统会自动报警. 给定一个非负整数列表,表示每个房子中存放的钱, 算一算,如果今晚去打劫,你最多可以得到多少钱 在不触动报警装置的情况下. 样例 给定 [3, 8, 4], 返回 8. 挑战 O(n) 时间复杂度 且 O(1) 存储. 标签 爱彼迎 动态规划 领英 方法一(O(n) 时间复杂度 且 O(n)…

你是一个专业的强盗,计划抢劫沿街的房屋.每间房都藏有一定的现金,阻止你抢劫他们的唯一的制约因素就是相邻的房屋有保安系统连接,如果两间相邻的房屋在同一晚上被闯入,它会自动联系警方.给定一个代表每个房屋的金额的非负整数列表,确定你可以在没有提醒警方的情况下抢劫的最高金额. 详见:https://leetcode.com/problems/house-robber/description/ Java实现: class Solution { public int rob(int[] nums) { in…

https://leetcode.com/problems/house-robber/ 题意: 一维数组,相加不相邻的数组,返回最大的结果. 思路: 一开始思路就是DP,用一维数组保存dp[i]保存如果偷第i间,此时可偷到多少.DP的方向不太好,所以效率很低. Runtime: 4 ms, faster than 17.53% class Solution { public: int rob(vector<int> &nums) { ; int len = nums.size(); )…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

198. 打家劫舍 198. House Robber 题目描述 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 每日一算法2019/5/8Day 5LeetCode198. House Robber 示例 1: 输入: [1,2,3,1] 输出: 4 解释:…

198. House Robber Easy You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system conn…

动态规划与分治方法都是通过组合子问题的解来求解原问题,区别在于:分治方法将问题划分为互不相交的子问题,递归求解子问题,再将它们的解组合起来,求出原问题的解.分治算法可能反复的求解某些公共子问题,从而使效率下降,例如用分治法求第n个斐波那契数.动态规划算法对每个子问题只求解一次,将其解保存在一个表格中,从而无需反复求解公共子问题.动态规划通常用来求解最优化问题. 应用动态规划方法求解的最优化问题应该具备两个要素: 1.最优子结构,如果一个问题的最优解包含其子问题的最优解,我们就称此问题具有最优子结…

------------------------------------------------------------第七周:Follow up question 1,寻找峰值 寻找峰值 描述 笔记 数据 评测 你给出一个整数数组(size为n),其具有以下特点: 相邻位置的数字是不同的 A[0] < A[1] 并且 A[n - 2] > A[n - 1] 假定P是峰值的位置则满足A[P] > A[P-1]且A[P] > A[P+1],返回数组中任意一个峰值的位置. 注意事项 数…