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array  排序总体有这几个函数sort.rsort.asort.arsort.ksort.krsort.usort.uasort.uksort. 一开始我记来记去总是有点混乱,后来认真对比后终于清楚了. sort就是对键值的排序是保持索引关系的即去除之前的键名变为按顺序数字索引. asort就是保持索引关系的排序. ksort 就是对键名进行排序. 里面加了r表示逆序排,加了u表示用户自定义排序. 就这么简单了.…
sort() 方法用于对数组的元素进行排序. 但是排序结果就有点坑了,都不按常规出牌的: // 看上去正常的结果: ['Google', 'Apple', 'Microsoft'].sort(); // ['Apple', 'Google', 'Microsoft']; // apple排在了最后: ['Google', 'apple', 'Microsoft'].sort(); // ['Google', 'Microsoft", 'apple'] // 无法理解的结果: [10, 20, 1…
五一假期回来,练习一下C#的一些知识,了解一下排序. 练习数据: , , , , , , , , }; 写一个类: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace ConsoleApplicationDemo { public class Bw { public int[] ArrayData…
Given a sorted array of integers nums and integer values a, b and c. Apply a function of the form f(x) = ax2 + bx + c to each element x in the array. The returned array must be in sorted order. Expected time complexity: O(n) Example: nums = [-4, -2,…
使用array.sort()对数组中对象的属性进行排序 <template> <div> <a @click="sortArray()">降序</a> </div> </template> <script> const oldArray = [{id: 1, name: 'Bek', age: '28'}, {id: 2, name: 'Evan', age: '12'}, {id: 3, name:…
Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…
var numberAry = [9,9,10,8,7,80,33,55,22]; numberAry.sort(); /*输出:10,22,33,55,7,8,80,9,9 上面的代码没有按照数值的大小对数字进行排序,只是按照首字母进行了排序,所以需要定义一个排序函数*/ 1.定义一个排序函数(正序) function sortNumber(a,b){ return a - b; } numberAry.sort(sortNumber); //输出:7,8,9,9,10,22,33,55,80…
1. sort → new_ary click to toggle source sort { |a, b| block } → new_ary Returns a new array created by sorting self. Comparisons for the sort will be done using the <=> operator or using an optional code block. The block must implement a comparison…
NSArray *sortedArray = [array sortedArrayUsingComparator: ^(id obj1, id obj2) { if ([obj1 integerValue] > [obj2 integerValue]) {        return (NSComparisonResult)NSOrderedDescending;    } if ([obj1 integerValue] < [obj2 integerValue]) {        retu…
数据 let data = [ {chinese: '蔡司', english: 'Chase',score:67}, {chinese: '艾伦', english: 'Allen',score:77}, {chinese: '左拉', english: 'Zola',score:87}, {chinese: '贝克', english: 'Baker',score:99}, {chinese: '伯格', english: 'Berg',score:55}, {chinese: '菲奇',…