LeetCode 348. Design Tic-Tac-Toe】的更多相关文章

题目如下: Tic-tac-toe is played by two players A and B on a 3 x 3 grid. Here are the rules of Tic-Tac-Toe: Players take turns placing characters into empty squares (" "). The first player A always places "X" characters, while the second pl…
1. Trees Tree is a recursive structure. 1.1 math nodes https://class.coursera.org/principlescomputing-001/wiki/view? page=trees 1.2 CODE无parent域的树 http://www.codeskulptor.org/#poc_tree.py class Tree: """ Recursive definition for trees plus…
题目:给定一个3*3的矩阵,是一个井字过三关游戏.开始为X先走,问你这个是不是一个合法的游戏.也就是,现在这种情况,能不能出现.如果有人赢了,那应该立即停止.那么可以知道X的步数和O的步数应该满足x==o+1或者x==o这种情况是允许的,这种情况是O赢.(x==o)这种情况是X赢(x==o+1).那么就可以知道 如果 ①.如果x>o+1(步数过多)||o>x(不符合x先行的规矩)  printf("no\n"); ②.如果是x赢了win(x)但是x!=o+1 不行 ③.如果…
题面: C. Team Tic Tac Toe Input file: standard input Output file: standard output Time limit: 1 second Memory limit: 256 megabytes   Farmer John owns 26 cows, which by happenstance all have names starting with different letters of the alphabet, so Farmer…
地址 https://www.acwing.com/solution/LeetCode/content/6670/ 题目描述A 和 B 在一个 3 x 3 的网格上玩井字棋. 井字棋游戏的规则如下: 玩家轮流将棋子放在空方格 (” “) 上.第一个玩家 A 总是用 “X” 作为棋子,而第二个玩家 B 总是用 “O” 作为棋子.“X” 和 “O” 只能放在空方格中,而不能放在已经被占用的方格上.只要有 3 个相同的(非空)棋子排成一条直线(行.列.对角线)时,游戏结束.如果所有方块都放满棋子(不为…
原题链接在这里:https://leetcode.com/problems/design-tic-tac-toe/ 题目: Design a Tic-tac-toe game that is played between two players on a n x n grid. You may assume the following rules: A move is guaranteed to be valid and is placed on an empty block. Once a w…
Design a Tic-tac-toe game that is played between two players on a n x n grid. You may assume the following rules: A move is guaranteed to be valid and is placed on an empty block.Once a winning condition is reached, no more moves is allowed.A player…
17.2 Design an algorithm to figure out if someone has won a game oftic-tac-toe. 这道题让我们判断玩家是否能赢井字棋游戏,有下面几点需要考虑: 1. 判断是否能赢hasWon函数是调用一次还是多次,如果是多次,我们可能为了优化而需要加入一些预处理. 2. 井字棋游戏通常是3x3的大小,我们是否想要实现NxN的大小? 3. 我们需要在代码紧凑,执行速度和代码清晰之间做出选择. #include <iostream> #…
N*N matrix is given with input red or black.You can move horizontally, vertically or diagonally. If 3 consecutive samecolor found, that color will get 1 point. So if 4 red are vertically then pointis 2. Find the winner. def tic_tac_toe(board,n) red,…
说明 用python实现了井字棋,整个框架是本人自己构思的,自认为比较满意.另外,90%+的代码也是本人逐字逐句敲的. minimax算法还没完全理解,所以参考了这里的代码,并作了修改. 特点 可以选择人人.人机.机人.机机四种对战模式之一 电脑玩家的AI使用了minimax算法,带apha-beta剪枝 电脑玩家在思考时,时时刻刻都有一个"假想敌".以便使得minimax算法运转起来 代码 作者:hhh5460 时间:2017年6月26日 # 棋盘 class Board(objec…