给定一个包含非负整数的 m x n 网格,请找出一条从左上角到右下角的路径,使得路径上的数字总和为最小. 说明:每次只能向下或者向右移动一步. 示例: 输入: [ [1,3,1], [1,5,1], [4,2,1] ] 输出: 7 解释: 因为路径 1→3→1→1→1 的总和最小. 基础的动态规划问题,适合理解动态规范的想法 没有像之前设一个行和列+1的数组,这样更直观些不容易犯错 class Solution { public int minPathSum(int[][] grid) {…
题目: A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish'…
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in t…
使用排列组合计算公式来计算,注意使用long long型数据保证计算不会溢出. class Solution { public: int M, N; ; //从根到叶子有多少个分支,就表示有多少种路径 //解空间是一个包含{0,1}的集合,总共有(m-1)+(n-1)个元素. void BackTrack(int x, int y) { if (x == M &&y == N) { //到达叶子节点 X++; return; } if (x < M) { BackTrack(x +…
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in t…
题面 A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' i…
