bfs 位置+状态 just need to calculate min value(only it is useful), so O(1*x) 挺有趣的一道题... #include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <string> #include <algorithm> #include <iostream&g…

目录 Contest Info Solutions A. Fifty-Fifty B. Ordinary Number C. Divide the Problems D. Blue and Red Balls E. Hopscotch Addict F. Small Products Contest Info Practice Link Solved A B C D E F 6/6 O O O O Ø O O 在比赛中通过 Ø 赛后通过 ! 尝试了但是失败了 - 没有尝试 Solutions A…

前四题都好水.后面两道题好难. C Divide the Problems #include <cstdio> #include <algorithm> using namespace std; inline int read() { , f = ; char ch = getchar(); ; ch = getchar(); } + ch - ; ch = getchar(); } return x * f; } ; int a[N]; int main() { int n =…

Small Products 思路: 整除分块+dp 打表发现,按整除分块后转移方向如下图所示,上面的块的前缀转移到下面的块 代码: #pragma GCC optimize(2) #pragma GCC optimize(3) #pragma GCC optimize(4) #include<bits/stdc++.h> using namespace std; #define y1 y11Z #define se second #define pi acos(-1.0) #define L…

A - Happy Birthday! Time limit : 2sec / Memory limit : 1000MB Score: 100 points Problem Statement E869120's and square1001's 16-th birthday is coming soon.Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces. E869…

没看到Beginner,然后就做啊做,发现A,B太简单了...然后想想做完算了..没想到C卡了一下,然后还是做出来了.D的话瞎想了一下,然后感觉也没问题.假装all kill.2333 AtCoder Beginner Contest 052 A题意: 输出大的面积? 思路: max(A*B,C*D); AtCoder Beginner Contest 052 B题意: 枚举过程,然后...太水了.. AtCoder Beginner Contest 052 C题意: 输出N!的因子个数mod1…

A - ABC/ARC Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Smeke has decided to participate in AtCoder Beginner Contest (ABC) if his current rating is less than 1200, and participate in AtCoder Regular Contest (ARC) oth…

AtCoder Beginner Contest 136 题目链接 A - +-x 直接取\(max\)即可. Code #include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 2e5 + 5; int main() { ios::sync_with_stdio(false); cin.tie(0); int a, b; cin >> a >> b; cout &…

AtCoder Beginner Contest 137 F 数论鬼题(虽然不算特别数论) 希望你在浏览这篇题解前已经知道了费马小定理 利用用费马小定理构造函数\(g(x)=(x-i)^{P-1}\) \[x=i,g(x)=0\] \[x\ne i ,g(x)=1\] 则我们可以构造 \[f(x)=\sum^{i=0}_{P-1}(-a_i*(x-i)^{P-1}+a_i)\] 对于第\(i\)条式子当且仅当\(a_i=1 \ and \ x=i\)时取到\(1\) 代码写的比较奇怪 const…

A - Rating Goal Time limit : 2sec / Memory limit : 256MB Score : 100 points Problem Statement Takahashi is a user of a site that hosts programming contests.When a user competes in a contest, the rating of the user (not necessarily an integer) changes…