Single Number III Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]…

Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题意:给定数组,除一个数仅出现一次外,其余都出现三次,找到仅出现一次的数字…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…

原题链接在这里:https://leetcode.com/problems/single-number-iii/ 题目: Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Giv…

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Note: The order…

问题: Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?   分析: 数组中的数除了一个只出现了一次之外,其它都出现了两次, 要找出只出…

题目意思:一个int数组,有一个数只出现一次,其他数均出现三次,找到这个唯一数 思路: 1.将所有数用2进制表示,计算每一位的数字和  1*3*n1+0*3*n2+c   唯一数对应位的数字(0或者1) 要求具有牢固的位运算基础 eg  10001010  10001010 10001010   10101001   10101001 10101001 11001010                   7,1,3,0,7,0,4,3 则唯一数为1,1,0,0,1,0,1,0 class So…

Description: Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. For example: Given nums = [1, 2, 1, 3, 2, 5], return [3, 5]. Not…

题意: 给一个数组,其中仅有两个元素是出现1次的,且其他元素均出现2次.求这两个特殊的元素? 思路: 跟查找单个特殊的那道题是差不多的,只是这次出现了两个特殊的.将数组扫一遍求全部元素的异或和 x,结果也就是这两个特殊的元素的异或和了.现在必须找到两个当中的一个,才能恢复出另外一个.注意到x的二进制位中必定有1,那么只需要找到其中任意一个1对应的整数,再将数组中所有该位为1的计算他们的异或和a,a就是结果了,而另一个数b=x^a. vector<int> singleNumber(vector…

[1]LeetCode 136 Single Number 题意:奇数个数,其中除了一个数只出现一次外,其他数都是成对出现,比如1,2,2,3,3...,求出该单个数. 解法:容易想到异或的性质,两个相同的数异或为0,那么把这串数从头到尾异或起来,最后的数就是要求的那个数. 代码如下: class Solution { public: int singleNumber(vector<int>& nums) { ; ;i<nums.size();i++) sum ^= nums[i…