Reorder the Books -- hdu -- 5500】的更多相关文章

http://acm.hdu.edu.cn/showproblem.php?pid=5500 Reorder the Books Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 920    Accepted Submission(s): 502 Problem Description dxy has a collection of…
Reorder the Books Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5500 Description dxy家收藏了一套书,这套书叫<SDOI故事集>,<SDOI故事集>有n(n≤19)n(n\leq 19)n(n≤19)本,每本书有一个编号,从111号到nnn号. dxy把这些书按编号从小到大,从上往下摞成一摞.dxy对这套书极其重视,不允许…
http://acm.hdu.edu.cn/showproblem.php?pid=5500 Reorder the Books Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 942    Accepted Submission(s): 519 Problem Description dxy has a collection of…
Reorder the Books Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 919    Accepted Submission(s): 501 Problem Description dxy has a collection of a series of books called "The Stories of SDOI&q…
Problem Description dxy has a collection of a series of books called “The Stories of SDOI”,There are n(n≤19) books in this series.Every book has a number from 1 to n. dxy puts these books in a book stack with the order of their numbers increasing fro…
Reorder the Books Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 179    Accepted Submission(s): 125 Problem Description dxy has a collection of a series of books called "The Stories of SDOI&q…
Reorder the Books 问题描述 dxy家收藏了一套书,这套书叫<SDOI故事集>,<SDOI故事集>有n(n\leq 19)n(n≤19)本,每本书有一个编号,从11号到nn号. dxy把这些书按编号从小到大,从上往下摞成一摞.dxy对这套书极其重视,不允许任何人动这套书. 有一天Evensgn到dxy家玩,dxy因为和妹子有约会,就让Evensgn自己待在他家.Evensgn对这套书非常好奇,偷偷的看了一下,结果发现这里面竟然有当年小E和小Q的故事.Evensgn看…
题意:   有一个1→n的排列形成的数列,我们要用最少的操作次数把这个数列从小到大排序,每次操作都是把一个数放到整个数列的最前面. 思路:        首先最大的数n是不用操作的(其他数操作好了,n自然在最后面了).先找到数n的位置,在n之前找n-1,若没找到n-1,则n-1需要操作,所有小于n-1的数均需要操作:若找到了n-1,再接着往前依次找n-2,n-3,...假如数k找不到了,那就是至少需要k次操作. 复杂度O(n). #pragma comment(linker, "/STACK:1…
题意: 有n本书,编号为1~n,现在书的顺序乱了,要求恢复成有序的样子,每次只能抽出其中一本并插到最前面,问最少需要多少抽几次? 思路: 如果pos[i]放的不是书i的话,则书i的右边所有的书都必须抽出来.抽出来的书必定可以回到它最终的位置上,即每本书最多抽出来1次,可以想象抽出来后直接扔掉,在剩下的书中找到一个有序,且最后一个元素为n,且等差为1的序列{...n-2,n-1,n}. //#include <bits/stdc++.h> #include <iostream> #i…
Problem Description dxy has a collection of a series of books called "The Stories of SDOI",There are n(n≤19) books in this series.Every book has a number from 1 to n. dxy puts these books in a book stack with the order of their numbers increasin…
Reorder the Books Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 930    Accepted Submission(s): 511 Problem Description dxy has a collection of a series of books called "The Stories of SDOI&…
美国「学券制」是怎样的一种制度?它为什么是共和党的执政政策?它在美国及其它地区有实施吗?效果如何?能否在保证公平的同时,通过市场提高教育质量? 作者:冉筱韬链接:https://www.zhihu.com/question/32168470/answer/59716622来源:知乎著作权归作者所有,转载请联系作者获得授权. 刚被邀请的时候一时没反应过来「学券」是什么东西,现在想想应该是指的 school voucher.课上学过一点,不是我特别熟悉的领域,试着回答一下.没有特别说明的都是美国的情…
Hdu6606 Distribution of books 题意 把一段连续的数字分成k段,不能有空段且段和段之间不能有间隔,但是可以舍去一部分后缀数字,求\(min(max((\sum ai ))\)其中\(\sum ai\)为一段的数字和 分析 最小化最大值问题通常我们要想到二分,所以答案的求法我们就解决了,但是二分我们怎么check呢?这个时候一点思路都没有,我们考虑暴力的算法,设dp[i]表示从1--i最多可以分成多少段,怎么转移,什么情况下可以转移呢? 显然\(dp[i]=max(dp…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2838 Cow Sorting Problem Description Sherlock's N (1 ≤ N ≤ 100,000) cows are lined up to be milked in the evening. Each cow has a unique "grumpiness" level in the range 1...100,000. Since grumpy cow…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1892 See you~ Problem Description Now I am leaving hust acm. In the past two and half years, I learned so many knowledge about Algorithm and Programming, and I met so many good friends. I want to say so…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4150 Powerful Incantation Description Some dangerous Witches invaded the garden city! As a righteous magician, james0zan want to find the most powerful incantation so he can beat those dangerous witches…
tarjan一直是我看了头大的问题,省选之前还是得好好系统的学习一下.我按照不同的算法在hdu上选题练习了一下,至少还是有了初步的认识.tarjan嘛,就是维护一个dfsnum[]和一个low[],在dfs树上处理图的连通性等问题.细节处的不同导致算法本身的不同作用. 有向图强连通缩点:大体思路是维护一个栈,满足访问一个点就push到栈里面,当满足low[now]==dfn[now]时出栈,用dfn[]更新low[]当且仅当下一个点在栈内(注意不是递归栈). #include<iostream>…
Sparse Graph Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 689    Accepted Submission(s): 238 Problem Description In graph theory, the complement of a graph G is a graph H on the same vertic…
See you~ Time Limit: 5000/3000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 4753    Accepted Submission(s): 1518 Problem Description Now I am leaving hust acm. In the past two and half years, I learned so many kno…
Balanced Sequence Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Chiaki has n strings s1,s2,…,sn consisting of '(' and ')'. A string of this type is said to be balanced:…
一看就是欧拉降幂,问题是怎么求$fib(a^b)$,C给的那么小显然还是要找循环节.数据范围出的很那啥..unsigned long long注意用防爆的乘法 /** @Date : 2017-09-25 15:17:05 * @FileName: HDU 2814 斐波那契循环节 欧拉降幂.cpp * @Platform: Windows * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : https://github.com/ * @Ve…
转载:from http://blog.csdn.net/qq_28236309/article/details/47818349 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029. 1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093. 1094.1095.1096.1097.1098.1106.1108.1157.116…
Minimum Inversion Number Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1394 Appoint description:  System Crawler  (2015-03-30) Description The inversion number of a given number sequence a1, a…
2019 Multi-University Training Contest 3 http://acm.hdu.edu.cn/contests/contest_show.php?cid=850 1004. Distribution of books 考虑二分答案,设当前二分出来的是\(x\). 设\(f_i\)表示前\(i\)个能分成最多的段数,使得每一段和都\(\leqslant x\). 转移显然,枚举一个\(j\),若\(s_i-s_j\leqslant x\)则转移,\(s_i\)表示前…
Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194    Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的.  一天,当他正在苦思冥想解困良策的…
Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3,4}, reorder it to {1,4,2,3}. 这道链表重排序问题可以拆分为以下三个小问题: 1. 使用快慢指针来找到链表的中点,并将链表从中…
http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…
http://acm.hdu.edu.cn/showproblem.php?pid=4859 题目大意: 在一个矩形周围都是海,这个矩形中有陆地,深海和浅海.浅海是可以填成陆地的. 求最多有多少条方格线满足两侧分别是海洋和陆地 这道题很神 首先考虑一下,什么情况下能够对答案做出贡献 就是相邻的两块不一样的时候 这样我们可以建立最小割模型,可是都说是最小割了 无法求出最大的不相同的东西 所以我们考虑转化,用总的配对数目 - 最小的相同的对数 至于最小的相同的对数怎么算呢? 我们考虑这样的构造方法:…
Special equations Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4569 Description Let f(x) = a nx n +...+ a 1x +a 0, in which a i (0 <= i <= n) are all known integers. We call f(x) 0 (mod…
The kth great number Time Limit:1000MS     Memory Limit:65768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4006 Description Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a nu…