一只小蜜蜂... Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description 有一只经过训练的蜜蜂只能爬向右侧相邻的蜂房,不能反向爬行.请编程计算蜜蜂从蜂房a爬到蜂房b的可能路线数. 其中,蜂房的结构如下所示. Input 输入数据的第一行是一个整数N,表示测试实例的个数,然后是N 行数据,每行包含两个…
一只小蜜蜂... Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 30082 Accepted Submission(s): 11099 Problem Description有一只经过训练的蜜蜂只能爬向右侧相邻的蜂房,不能反向爬行.请编程计算蜜蜂从蜂房a爬到蜂房b的可能路线数.其中,蜂房的结构如下所示. Input输入数据的第一行…
一只小蜜蜂... 链接:http://acm.hdu.edu.cn/showproblem.php?pid=2044 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 95054 Accepted Submission(s): 33882 Problem Description 有一只经过训练的蜜蜂只能爬向右侧相邻的蜂房,不能反向爬行…
题目:一只小蜜蜂 递归做法: #include<cstdio> #include<iostream> #include<stdlib.h> #include<stack> #include<string> using namespace std; int cnt=0;//count int a,b; //int flag=0; int tran[3]={1,2};//坐标移动 void done(int x) { int begin=0,bet=…
