http://poj.org/problem?id=3071 题意:有2^n个队伍,给出每两个队伍之间的胜率,进行每轮淘汰数为队伍数/2的淘汰赛(每次比赛都是相邻两个队伍进行),问哪只队伍成为冠军概率最大. 很基础. 代码 #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #include<cmath> #include<queue> u…

Description Consider a single-elimination football tournament involving 2n teams, denoted 1, 2, …, 2n. In each round of the tournament, all teams still in the tournament are placed in a list in order of increasing index. Then, the first team in the l…

题意:n支队伍两两进行比赛,求最有可能获得冠军的队伍. 解题关键:概率dp,转移方程:$dp[i][j] +  = dp[i][j]*dp[i][k]*p[j][k]$表示第$i$回合$j$获胜的概率,原理为全概率公式. 如何判断相邻,通过位运算. 概率dp的过程就像是模拟的过程 复杂度:$O(n{2^n}{2^n})$ #include<cstdio> #include<cstring> #include<algorithm> #include<cstdlib&…

                                                                                             Football Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 2590   Accepted: 1315 Description Consider a single-elimination football tournament inv…

G - Football Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Consider a single-elimination football tournament involving 2n teams, denoted 1, 2, …, 2n. In each round of the tournament, all teams…

Football Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 2667   Accepted: 1361 Description Consider a single-elimination football tournament involving 2n teams, denoted 1, 2, -, 2n. In each round of the tournament, all teams still in the…

题目链接 不1Y都对不住看过那么多年的球.dp[i][j]表示i队进入第j轮的概率,此题用0-1<<n表示非常方便. #include <cstdio> #include <cstring> #include <iostream> #include <cmath> #include <algorithm> using namespace std; ][]; ][]; int main() { int n,i,j,mod,c,k,ans…

期望概率DP简单题 从[1,1]点走到[r,c]点,每走一步的代价为2 给出每一个点走相邻位置的概率,共3中方向,不动: [x,y]->[x][y]=p[x][y][0] ,  右移:[x][y]->[x][y+1]=p[x][y][1];  左移:[x][y]->[x+1][y]=p[x][y][2]; 问最后走到[r,c]的期望 dp[i][j]为从[i][j]点走到[r][c]的期望 有方程: dp[i][j]=    (dp[i][j]+2)*p[i][j][0]  +   (d…

传送门 概率dp简单题. 设f[i][j]表示前i轮j获胜的概率. 如果j,k能够刚好在第i轮相遇,找规律可以发现j,k满足: (j−1)>>(i−1)" role="presentation" style="position: relative;">(j−1)>>(i−1)(j−1)>>(i−1)^1==(k−1)>>(i−1)" role="presentation"…

poj3071 Football 题意:有2^n支球队比赛,每次和相邻的球队踢,两两淘汰,给定任意两支球队相互踢赢的概率,求最后哪只球队最可能夺冠. 我们可以十分显然(大雾)地列出转移方程(设$f[ i ][ j ]$为第 $j$ 支球队踢赢第 $i$ 场比赛的概率,$k$为枚举的对手): $f[ i ][ j ] += f[ i-1 ][ j ] * f[ i-1 ][ k ] * p[ j ][ k ]$ 现在问题来了:怎么枚举 k, k的范围是啥 我们先列出比赛的模型(a Tower,n=…