You can fail at what you don't want, so you might as well take a chance on doing what you love. 做不想做的事可能会失败,倒不如给自己一个机会做你爱做的事.(Jim Carrey)…

http://unixpapa.com/js/mouse.html Javascript Madness: Mouse Events Jan WolterAug 12, 2011 Note: I have stopped updating this page. At this point nearly all popular browsers are have achieved a good level of compatibility on most of these features, an…

http://www.gamasutra.com/blogs/ChrisSimpson/20140717/221339/Behavior_trees_for_AI_How_they_work.php by Chris Simpson on 07/17/14 09:35:00 pm       27 comments       The following blog post, unless otherwise noted, was written by a member of Gamasutra…

2434: [Noi2011]阿狸的打字机 Time Limit: 10 Sec  Memory Limit: 256 MBSubmit: 2545  Solved: 1419[Submit][Status][Discuss] Description 阿狸喜欢收藏各种稀奇古怪的东西,最近他淘到一台老式的打字机.打字机上只有28个按键,分别印有26个小写英文字母和'B'.'P'两个字母.经阿狸研究发现,这个打字机是这样工作的:l 输入小写字母,打字机的一个凹槽中会加入这个字母(这个字母加在凹槽的最…

3172: [Tjoi2013]单词 Time Limit: 10 Sec  Memory Limit: 512 MBSubmit: 3198  Solved: 1532[Submit][Status][Discuss] Description 某人读论文,一篇论文是由许多单词组成.但他发现一个单词会在论文中出现很多次,现在想知道每个单词分别在论文中出现多少次. Input 第一个一个整数N,表示有多少个单词,接下来N行每行一个单词.每个单词由小写字母组成,N<=200,单词长度不超过10^6…

前置技能:AC自动机 假设我们有了一个AC自动机,然后在上面进行字符串匹配. 上面是一个有四个字符串的AC自动机(abcde.aacdf.cdf.cde),虚线是fail指针,实线是转移. 这是上一次讲AC自动机的时候的匹配代码: int match(char* s) { ; ;s[i];i++) { int c=s[i]-'a'; cur=ch[cur][c]; for(int f=cur;f!=rot;f=fail[f]) ans+=cnt[f], cnt[f]=; } return ans…

如果a串是另b串的后缀,那么在trie图上沿着b的fail指针走一定可以走到a串. 而a串在b串里出现多少次就是它是多少个前缀的后缀. 所以把fail边反向建树维护个dfs序就行了. 并不是很难...但没想出来TAT #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #define N 200005 #define inf 0x3f3f3f3f using na…

E. e-Government time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output The best programmers of Embezzland compete to develop a part of the project called "e-Government" — the system of automa…

3881: [Coci2015]Divljak Time Limit: 20 Sec  Memory Limit: 768 MBSubmit: 508  Solved: 158[Submit][Status][Discuss] Description Alice有n个字符串S_1,S_2...S_n,Bob有一个字符串集合T,一开始集合是空的. 接下来会发生q个操作,操作有两种形式: “1 P”,Bob往自己的集合里添加了一个字符串P. “2 x”,Alice询问Bob,集合T中有多少个字符串包…

throw new GradleException("conditions are not met") 参考 How to fail/stop task immediately if some conditions are not met…