Who's in the Middle[HDU1157]】的更多相关文章

Who's in the Middle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16668    Accepted Submission(s): 7471 Problem Description FJ is surveying his herd to find the most average cow. He wants to k…
Who's in the Middle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9411    Accepted Submission(s): 4538 Problem Description FJ is surveying his herd to find the most average cow. He wants to k…
坏味道--中间人(Middle Man) 特征 如果一个类的作用仅仅是指向另一个类的委托,为什么要存在呢? 问题原因 对象的基本特征之一就是封装:对外部世界隐藏其内部细节.封装往往伴随委托.但是人们可能过度运用委托.比如,你也许会看到一个类的大部分有用工作都委托给了其他类,类本身成了一个空壳,除了委托之外不做任何事情. 解决方法 应该运用 移除中间人(Remove Middle Man),直接和真正负责的对象打交道. 收益 减少笨重的代码. 何时忽略 如果是以下情况,不要删除已创建的中间人: 添…
2653: middle Time Limit: 20 Sec  Memory Limit: 512 MBSubmit: 1298  Solved: 734[Submit][Status][Discuss] Description 一个长度为n的序列a,设其排过序之后为b,其中位数定义为b[n/2],其中a,b从0开始标号,除法取下整. 给你一个长度为n的序列s. 回答Q个这样的询问:s的左端点在[a,b]之间,右端点在[c,d]之间的子序列中,最大的中位数. 其中a<b<c<d. 位置…
Implement an algorithm to delete a node in the middle of a singly linked list, given only access to that node. Have you met this question in a real interview?     Example Given 1->2->3->4, and node 3. return 1->2->4 LeetCode上的原题,请参见我之前的博客De…
img style="vertical-align:middle;" src="<%=basePath%>/images/ckpy.png" ></img 图片标签在容器中上下居中.…
Sort a linked list in O(n log n) time using constant space complexity. 思路: 用归并排序.设输入链表为S,则先将其拆分为前半部分链表A,后半部分链表B.注意,要把A链表的末尾置为NULL.即要把链表划分为两个独立的部分,防止后面错乱. #include <iostream> #include <vector> #include <algorithm> #include <queue> #…
Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}, reorder it to {1,4,2,3}. 思路: 先把链表分成两节,后半部分翻转,然后前后交叉连接. 大神的代码比我的简洁,注意分两节时用快…
Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by…
我要垂直居中我要垂直居中我要垂直居中我要垂直居中我要垂直居中垂直居中垂直居中垂直居中中垂直居中垂直居中   <!-- 第一步:主题元素display:inline-block;第二步:插入辅助元素,宽度0:高度100%:第三步:让span和i元素 vertical-align:middle; -->…