There is a tree of N nodes which are numbered from 1 to N. Unfortunately, its edges are missing so we don't know how the nodes are connected. Instead we know: 1. Which nodes are leaves 2. The distance (number of edges) between any pair of leaves 3. T…

D. Tree Construction 题目连接: http://www.codeforces.com/contest/675/problem/D Description During the programming classes Vasya was assigned a difficult problem. However, he doesn't know how to code and was unable to find the solution in the Internet, so…

There is a tree of n vertices. For each vertex a list of all its successors is known (not only direct ones). It is required to restore the tree or to say there is no such tree. Input The first line contains a single integer n (1 ≤ n ≤ 1000) — the num…

微软 2017春招真题 题目 There is a tree of N nodes which are numbered from 1 to N. Unfortunately, its edges are missing so we don't know how the nodes are connected. Instead we know:   Which nodes are leaves   The distance (number of edges) between any pair o…

Is It A Tree? Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 28399   Accepted: 9684 Description A tree is a well-known data structure that is either empty (null, void, nothing) or is a set of one or more nodes connected by directed edge…

[题目链接]:https://hihocoder.com/problemset/problem/1490 [题意] 给你一棵树的以下信息: 1.节点个数 2.给出树的每一层从左到右的顺序每个节点的编号 3.哪些节点是叶子节点 然后树中的边被去掉了; 让你复原出原图(树) [题解] 这是道模拟题. 从最下层到上一层,从最左边的节点到右边的节点往上接父亲节点就好; 具体实现的时候; 直接找上一层最左边的且没被其他节点当爸爸的.且不为叶子节点的节点当爸爸就好; 当了爸爸之后 更新那个爸爸到其他所有节点…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4925 解题报告:给你n*m的土地,现在对每一块土地有两种操作,最多只能在每块土地上进行两种操作,第一种是种苹果树操作,第二种是施肥操作,种苹果树操作可以使得该块地 长出一个苹果,施肥操作可以使得与这块土地相邻的土地的苹果产量变为原来的两倍,问可以得到的最多的苹果数量是多少? 例如一个4*4的土地,用1表示在该土地上做第一种操作,0表示在该土地上做第二种操作,可以得到最多苹果的操作如下: 0 1 0…

构造. 从最后一层开始往上构造.最后一层肯定都是叶子结点,距离为2的肯定是同一个父亲,确定好了父亲之后,可以确定上一层每个节点之间的距离,以及上一层每个节点到还未确定的叶子节点之间的距离. #include<bits/stdc++.h> using namespace std; int n,m,k; vector<]; ],L[],h[]; ][]; ]; int main() { scanf("%d%d%d",&n,&m,&k); ;i<…

题意: 一棵树,给出每个点的后代们,问你这棵树是否存在,存在就给出这棵树 n<=1000 思路: 对祖先->后代建立有向图,跑拓扑排序.跑的时候不断更新父亲并判断答案的存在性,同时注意一种情况:一个点他儿子是他的后代,同样也得是他父亲的后代,这样传递下去就一定是所有祖宗的后代. 代码: 代码参考网上的 #include<iostream> #include<cstdio> #include<algorithm> #include<cmath> #…

作者:ssslinppp       1. 摘要 2. tree的相关介绍 3. 异步加载tree数据,并实现tree的折叠展开 3.1 功能说明: 3.2 前台代码 3.3 后台代码 4. 其他 1. 摘要 easyui相关的介绍可以上其官网或者百度去搜索,这里不做介绍. Easyui Tree的使用,官网或者easyui中文网站,也有相关介绍,但是官方提供的实例所使用的json是写死的,不是后台实时读取的.在实际的项目中,要显示的tree数据,一般都是从数据库中读取,然后通过通过ajax或者…