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t组询问,每次给出数列长度n 以及两个长度为n的数列{ai​}和{bi​}. 有三种操作:ai​−1, bi​−1以及ai​,bi​同时− 1 -1−1. 问最少多少步以后可以让两个数列变成常数数列. You have n gifts and you want to give all of them to children. Of course, you don't want to offend anyone, so all gifts should be equal between each…
A. Remove Smallest 题意:数组是否满足任意i,j保证|ai-aj|<=1,如果都可以满足,输出YES,否则输出NO 思路:直接排序遍历即可 代码: 1 #include<iostream> 2 #include<algorithm> 3 #include<cstring> 4 #include<cstdio> 5 #include<cmath> 6 #include<queue> 7 #include<v…
UVa 10618 Fixing the Great Wall 题目:  http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=36139 思路:   数轴上有n个点需要修复,每个点有信息c,x,d 表示位于x且在t时修缮的费用是c+d*t,找一个修缮序列使n个点能全部修缮且有费用最小. 可以发现:在任意时刻,修缮完的点都是连续的,因为修缮不需要时间,将一些点“顺手”修缮了肯定不差. d[i][j][k],表示已经将i-j个点修缮…
PolandBall and Gifts 转换成置换群后, 对于最大值我们很好处理. 对于最小值, 只跟若干个圈能否刚好组能 k 有关. 最直观的想法就是bitset优化背包, 直接搞肯定T掉. 我们能再发掘一些性质, 就是本质不能的圈的大小最多有sqrt(n)个, 因为1 + 2 + 3 ... + n = (n + 1) * n / 2 所以对于每个不同的数二进制优化一下就可以过啦. 感觉这种题就很有意思.. #include<bits/stdc++.h> #define LL long…
Gifts 感觉题解写的就是坨不知道什么东西.. 看得这个题解. #include<bits/stdc++.h> #define LL long long #define LD long double #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int&…
48 Fixing relationship Problems with Humor 用幽默解决人际关系问题 ①We've all heard that laughter is the best medicine, and it's true. Laughter relieves tensions and stress, elevates mood, enhances creativity,and boosts energy. Laughter also plays an essential r…
D. Gifts by the List 题目连接: http://www.codeforces.com/contest/681/problem/D Description Sasha lives in a big happy family. At the Man's Day all the men of the family gather to celebrate it following their own traditions. There are n men in Sasha's fam…
题目大意:长城(视作x正半轴)有n处破损.有一个智能修复机器人,它的初始位置和移动速度已知.每处破损处都有一组参数(x,c,d),x表示位置,c.d表示在时间t后再修复该处破损的花费为d*t+c.求用一个机器人修复所有破损的最小花费. 题目分析:要想最终代价最低,就不能跳跃着修复,也就是经过一段时间后已经修复好的破损应是一段连续区间.定义dp(i,j,k)表示修好(i,j)后机器人停留在k(0表示在左端,1表示在右端)端的费用.修复某处破损的代价虽然不是定值,但却是随着时间线性增长的,所以当修复…
题目链接: F. PolandBall and Gifts time limit per test 1.5 seconds memory limit per test 256 megabytes input standard input output standard output It's Christmas time! PolandBall and his friends will be giving themselves gifts. There are n Balls overall.…
[UVA-1336]Fixing the Great Wall 一开始把题看错了……直接用的整数存储答案:之后用double存最后输出答案的时候取整就AC了…
*本文主要记录及分享学习到的知识,算不上原创 *参考文章见链接. 本文简单介绍一下Variable fixing heuristic,这个算法同样以local search为核心框架,它的特点在于定义邻域结构的方式. 目录 Hard variable fixing heuristic Soft Variable fixing heuristic Hard Variable fixing heuristic Variable fixing heuristic 常常与Cplex一起使用.就像刚才提到…
圣诞老人的礼物-Santa Clau’s Gifts  Descriptions: 圣诞节来临了,在城市A中圣诞老人准备分发糖果,现在有多箱不同的糖果,每箱糖果有自己的价值和重量,每箱糖果都可以拆分成任意散装组合带走.圣诞老人的驯鹿最多只能承受一定重量的糖果,请问圣诞老人最多能带走多大价值的糖果. Input 第一行由两个部分组成,分别为糖果箱数正整数n(1 <= n <= 100),驯鹿能承受的最大重量正整数w(0 < w < 10000),两个数用空格隔开.其余n行每行对应一箱…
F. PolandBall and Gifts   It's Christmas time! PolandBall and his friends will be giving themselves gifts. There are n Balls overall. Each Ball has someone for whom he should bring a present according to some permutation p, pi ≠ i for all i. Unfortun…
time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Sasha lives in a big happy family. At the Man's Day all the men of the family gather to celebrate it following their own traditions. There are n…
Mr. Cui is working off-campus and he misses his girl friend very much. After a whole night tossing and turning, he decides to get to his girl friend's city and of course, with well-chosen gifts. He knows neither too low the price could a gift be sinc…
http://codeforces.com/gym/102394/problem/F F. Fixing Banners time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Harbin, whose name was originally a Manchu word meaning "a place for drying fish…
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F. Fixing Banners time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Harbin, whose name was originally a Manchu word meaning "a place for drying fishing nets", grew from a small rural set…
the i-th necklace has a brightness ai, where all the ai are pairwise distinct (i.e. all ai are different), the i-th bracelet has a brightness bi, where all the bi are pairwise distinct (i.e. all bi are different). Kuroni wants to give exactly one nec…
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题目链接:http://codeforces.com/problemset/problem/363/C 题目意思:纠正两种类型的typos.第一种为同一个字母连续出现3次以上(包括3次):另一种为两个不同的字母各出现2次.需要把使用最少次数而纠正好的word输出来. 为了方便操作,这里我都是通过删去后一个字母来纠正typo的,即如果是wwaattyy,假设看成两组:wwaa和ttyy,那么纠正完的分别是:wwa和tty.至于第一种类型的typo比第二种简便,只需要把同一个字母删除到只剩下2个即可…
I've recently been accumulating some MySQL configuration variables that have defaults which have proven to be problematic in a high-volume production environment. The thing they all have in common is a network blip or two can trigger some very undesi…
搞linux的最怕的就是panic.满屏的报错不知头绪,百度出来的还都是抄来抄去的垃圾. 我遇到的错误已经解决,所以不想再看到报错了..google出来两个没有上下文的文本,因为和他们差不多,在下面贴出来供百度用户们搜索..: 解决办法是:打开/usr/lib/opkg/info/XXX.postinst  把里面第四行改成load_modules.Enjoy! opkg install qos-scripts   #(whatever)Package qos-scripts (1.2.1-6)…
http://www.codewars.com/kata/55c423ecf847fbcba100002b/train/csharp Oh no, Timmy's received some hate mail recently but he knows better. Help timmy fix his regex filter so he can be awesome again! using System; using NUnit.Framework; System.Text.Regul…
题意: 在一条线上,有n个坏的地方要修机器人修,机器人的移动速度V,若坏的地方立即被修花费ci,若没修,每单位时间增加d,出去机器人的开始位置,求修完n个地方的最小花费. 分析: 非常经典,求解“未来费用”的问题,考虑区间完成最后一定在区间边界上,才能保证最优.dp[i][j][k]表示修完区间长i起点为j的所有地点,k=0最后点在左边界,k=1最后点在右边界,花费最小的费用.现在考虑随着时间的花费增加的费用.时间*未走过的点的d之和为增加的费用. dp[i][j][0]=min(dp[i-1]…
题意:给你一个森林,表示其祖先关系(自己也是自己的祖先),每个人有一个礼物(要送给这个人的固定的一个祖先) 让你构造一个序列,使得的对于每个人,这个序列中第一个出现的他的祖先,是他要送礼物的的那个祖先 分析:这个序列满足 1:我们这个序列只需要出现那些被送礼物的人就好了 2:这个序列的元素保证,如果x是y的祖先,那么x在y的后面 具体:这个序列可以通过dfs构造,然后最后check一下这个序列 注:check的过程和构造序列的dfs过程同步 #include <cstdio> #include…
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