[题解]HDU5845 Best Division (trie树) 题意:给定你一个序列(三个参数来根),然后请你划分子段.在每段子段长度小于等于\(L\)且子段的异或和\(\le x\)的情况下最大化分出子段的个数 区间/子段/序列这种东西一大性质就是右端点之后与前面无关. \(dp(i)\)表示上一个右端点是\(i\)且前面分出来的子段都满足条件的最多子段个数. 直接转移\(O(n^2)\)考虑优化这个东西,子段转前缀和是应该记起来的套路,现在问题就是变成查询两个前缀和的异或值是否满足条件.…

递归写法,好久不写很容易就gg了... dp[i]=max(dp[j])+1,并且s[i]XORs[j]<=x  01字典树优化一下转移. #include <bits/stdc++.h> #define ll long long using namespace std; ; ll a[N], X; struct Tire{ ], val[N], dp[N]; void init(){ tot = ; node[][] = node[][] = val[] = ; dp[] = -1e9…

1.在python2 中导入未来的支持的语言特征中division(精确除法),即from __future__ import division ,当我们在程序中没有导入该特征时,"/"操作符执行的只能是整除,也就是取整数,只有当我们导入division(精确算法)以后,"/"执行的才是精确算法. 如: #python 2.7.6 Python 2.7.6 (default, Nov 10 2013, 19:24:18) [MSC v.1500 32 bit (In…

Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example:Given a / b =…

Did you ever have the feeling that adding people doesn't help in software development? Did you ever think about the reason? And do you have any idea to make a change? Traditional software engineering emphasizes on division of work by modules, values…

Contestants Division   Description In the new ACM-ICPC Regional Contest, a special monitoring and submitting system will be set up, and students will be able to compete at their own universities. However there’s one problem. Due to the high cost of t…

题目传送门 /* 暴力:对于每一个数都判断,是否数字全都使用过一遍 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <queue> usin…

GDC2016[全境封锁(Tom Clancy's The Division)]对为何对应Eye Tracked System,以及各种优点的演讲报告 原文 4Gamer編集部:松本隆一 http://www.4gamer.net/games/241/G024173/20160317137/         北美时间2016年3月16日,在旧金山举办的Games Developers Conference 2016上,进行了关于[全境封锁(Tom Clancy's The Division)]的…

Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0. Example: Given a / b =…

IMO, version 1 better than version 2, version 2 better than version 3. make some preprocess to make you code simple and efficient. Here divide the input by 2, so you don't have to do dividsion on each loop. version 1 is best thanks to http://www.cnbl…