397 Integer Replacement 整数替换】的更多相关文章

给定一个正整数 n,你可以做如下操作:1. 如果 n 是偶数,则用 n / 2替换 n.2. 如果 n 是奇数,则可以用 n + 1或n - 1替换 n.n 变为 1 所需的最小替换次数是多少?示例 1:输入:8输出:3解释:8 -> 4 -> 2 -> 1示例 2:输入:7输出:4解释:7 -> 8 -> 4 -> 2 -> 1或7 -> 6 -> 3 -> 2 -> 1详见:https://leetcode.com/problems/i…
Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Input: 8 Outp…
397. Integer Replacement QuestionEditorial Solution My Submissions   Total Accepted: 5878 Total Submissions: 21519 Difficulty: Easy Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can…
Week3 - 397. Integer Replacement 397.Integer Replacement - Medium Given a positive integer n and you can do operations as follow: 1.If n is even, replace n with n/2. 2.If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum num…
[LeetCode]397. Integer Replacement 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/integer-replacement/description/ 题目描述: Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you…
先正统做法. public class Solution { public int integerReplacement(int n) { if(n == 1) return 0; int res = 0; while(n != 1) { if(n % 2 == 0) { n/=2; res++; } else return res + odd(n); } return res; } public int odd(int n) { return Math.min(integerReplaceme…
整数替换 给定一个正整数 n,你可以做如下操作: 1. 如果 n 是偶数,则用 n / 2替换 n.2. 如果 n 是奇数,则可以用 n + 1或n - 1替换 n.n 变为 1 所需的最小替换次数是多少? 示例 1: 输入: 8 输出: 3 解释: 8 -> 4 -> 2 -> 1 示例 2: 输入: 7 输出: 4 解释: 7 -> 8 -> 4 -> 2 -> 1 或 7 -> 6 -> 3 -> 2 -> 1 import stat…
397. 整数替换 给定一个正整数 n,你可以做如下操作: 如果 n 是偶数,则用 n / 2替换 n. 如果 n 是奇数,则可以用 n + 1或n - 1替换 n. n 变为 1 所需的最小替换次数是多少? 示例 1: 输入: 8 输出: 3 解释: 8 -> 4 -> 2 -> 1 示例 2: 输入: 7 输出: 4 解释: 7 -> 8 -> 4 -> 2 -> 1 或 7 -> 6 -> 3 -> 2 -> 1 class Solu…
Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Input: 8 Outp…
题目: 颠倒整数 将一个整数中的数字进行颠倒,当颠倒后的整数溢出时,返回 0 (标记为 32 位整数). 样例 给定 x = 123,返回 321 给定 x = -123,返回 -321 解题: 直接反转,越界处理好炒蛋 Java程序: public class Solution { /** * @param n the integer to be reversed * @return the reversed integer */ public int reverseInteger(int n…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 题意: 给定一个10进制整数,翻转它. Solution1: directly do the simulation. Two tricky parts to be hand…
Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throug…
[抄题]: 将一个整数中的数字进行颠倒,当颠倒后的整数溢出时,返回 0 (标记为 32 位整数).   样例 给定 x = 123,返回 321 给定 x = -123,返回 -321 [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: [奇葩输出条件]: [奇葩corner case]: 负数.末尾有0均可用该方法处理 [思维问题]: [一句话思路]: 分离一位数.一边变长 另一边变短 [输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不…
题目: 给定一个整数,求将该整数逆转之后的值: 举例: Example1: x = 123, return 321Example2: x = -123, return -321 解题思路: 在这里只用说明几个要注意的点: 1.  如果该整数是负数,-123,则逆转之后为-321,因此需要从第一位开始逆转,而不是第0位: 2.  如果整数例如:12300,则逆转后为321,而不是00321,因此逆转后,需要去除前面的0: 3.  如果整数例如:2147483647,则逆转后为7463847412…
题目等级:Easy 题目描述: Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21    题意:给出一个 32 位的有符号整数,你需要将这个整数中每位上的数字进行反转. 解题思路:   本题很简单,我们给出以下两种方法.  …
题目 Given a 32-bit signed integer, reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123,return -321 Example3: x = 120, return 21 思路 问题的关键在于对溢出的判断. 思路1:用long或者long long 直接用long或者long long计算,这样就保证不会溢出,再判断反转后的数字是否溢出. 思路2:stoi()…
0x00      Preview Last few passage I didn't conclude some important points and a general direction of the learning route of PWN. I browser some passages and finally I found one maybe suitable and reasonable for most PWN lovers: 0x01  Integer Overflow…
Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…
Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…
Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throu…
Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Input: 8 Outp…
Reverse digits of an integer. Returns 0 when the reversed integer overflows (signed 32-bit integer). Have you met this question in a real interview?     Example Given x = 123, return 321 Given x = -123, return -321 LeetCode上的原题,请参见我之前的博客Reverse Integ…
Implement atoi to convert a string to an integer. If no valid conversion could be performed, a zero value is returned. If the correct value is out of the range of representable values, INT_MAX (2147483647) or INT_MIN (-2147483648) is returned. int my…
描述: 给定32位整数,反转,如321转成123. 解决: 关键是溢出检测: int reverse(int x) { ; int temp; while (x) { temp = ret * + x % ; != ret) ; ret = temp; x /= ; } return ret; } 看了下其他答案,还有一些思路: 先声明个long,看最后是否溢出,这样只有long是64位时可以,或者用int64_t. 还有先转字符串反转再转数字的.…
潜在问题:(1)随着求和可能精度会溢出int 范围,需要使用long 来辅助判断是否溢出,此时返回 0 Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. For the purpose of this problem, assume that your function returns…
Question Given a positive integer n and you can do operations as follow: If n is even, replace n with n/2. If n is odd, you can replace n with either n + 1 or n - 1. What is the minimum number of replacements needed for n to become 1? Example 1: Inpu…
Given a 32-bit signed integer, reverse digits of an integer.Example 1:Input: 123Output:  321Example 2:Input: -123Output: -321Example 3:Input: 120Output: 21Note:Assume we are dealing with an environment which could only hold integers within the 32-bit…
给定一个正整数 n,将其拆分为至少两个正整数的和,并使这些整数的乘积最大化. 返回你可以获得的最大乘积.例如,给定 n = 2,返回1(2 = 1 + 1):给定 n = 10,返回36(10 = 3 + 3 + 4).注意:你可以假设 n 不小于2且不大于58. 详见:https://leetcode.com/problems/integer-break/description/ C++: class Solution { public: int integerBreak(int n) { i…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only store integers within…
Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. Example 1: Input: 2 Output: 1 Explanation: 2 = 1 + 1, 1 × 1 = 1. Example 2: Input:…