Problem 2102 Solve equation Accept: 881    Submit: 2065 Time Limit: 1000 mSec    Memory Limit : 32768 KB  Problem Description You are given two positive integers A and B in Base C. For the equation: A=k*B+d We know there always existing many non-nega…

B. Little Dima and Equation time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following proble…

 FZU 2102   Solve equation Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u  Practice Description You are given two positive integers A and B in Base C. For the equation: A=k*B+d We know there always existing many non-nega…

题意: 有1~9数字各有a1, a2, -, a9个, 有无穷多的+和=. 问只用这些数字, 最多能组成多少个不同的等式x+y=z, 其中x,y,z∈[1,9]. 等式中只要有一个数字不一样 就是不一样的 思路: 计算下可以发现, 等式最多只有36个. 然后每个数字i的上界是17-i个 可以预先判掉答案一定是36的, 然后直接暴力搜索每个等式要不要就好了. 注意剪枝即可 ; int a[maxn]; bool flag36; int ans; struct Equation { int x, y…

#对coursera上Andrew Ng老师开的机器学习课程的笔记和心得: #注:此笔记是我自己认为本节课里比较重要.难理解或容易忘记的内容并做了些补充,并非是课堂详细笔记和要点: #标记为<补充>的是我自己加的内容而非课堂内容,参考文献列于文末.博主能力有限,若有错误,恳请指正: #---------------------------------------------------------------------------------# 多元线性回归的模型: #-----------…

Codeforces Round #262 (Div. 2) B B - Little Dima and Equation B. Little Dima and Equation time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Dima misbehaved during a math lesson a lot a…

,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, ,, 1 % Exercise 1: Linear regression with multiple variables %% Initialization %% ================ Part 1: Featu…

Can you solve this equation? Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Now,given the equation *x^ + *x^ + *x^ + *x + == Y,can you find its solution between and ; No…

http://acm.hust.edu.cn/vjudge/contest/view.action?cid=27938#problem/E 题目大意:Given, n, count the number of solutions to the equation x+2y+2z=n, where x,y,z,n are non negative integers. 解题思路:只对一个枚举由此推算出另外两个的种类,千万不要都枚举!!! #include<iostream> #include<…

Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7156    Accepted Submission(s): 3318 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y…

H - The equation Time Limit:250MS     Memory Limit:4096KB     64bit IO Format:%I64d & %I64u Submit Status Practice SGU 106 Description There is an equation ax + by + c = 0. Given a,b,c,x1,x2,y1,y2 you must determine, how many integer roots of this eq…

Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7493    Accepted Submission(s): 3484 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,…

继续考虑Liner Regression的问题,把它写成如下的矩阵形式,然后即可得到θ的Normal Equation. Normal Equation: θ=(XTX)-1XTy 当X可逆时,(XTX)-1XTy = X-1,(XTX)-1XTy其实就是X的伪逆(Pseudo inverse).这也对应着Xθ = y ,θ = X-1y 考虑特殊情况 XTX 不可逆 解决办法: 1)考虑是否有冗余的特征,例如特征中有平方米,还有平方厘米,这两个特征就是冗余的,解决办法是去掉冗余 2)再有就是n…

http://acm.hdu.edu.cn/howproblem.php?pid=2199 Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 13468    Accepted Submission(s): 6006 Problem Description Now,given the…

蓝桥杯--Quadratic Equation 问题描述 求解方程ax2+bx+c=0的根.要求a, b, c由用户输入,并且可以为任意实数. 输入格式:输入只有一行,包括三个系数,之间用空格格开. 输出格式:输出只有一行,包括两个根,大根在前,小根在后,无需考虑特殊情况,保留小数点后两位. 输入输出样例样例输入2.5 7.5 1.0样例输出-0.14 -2.86 java code: import java.util.*;import java.text.*;public class Yiyu…

time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Dima misbehaved during a math lesson a lot and the nasty teacher Mr. Pickles gave him the following problem as a punishment. Find all…

Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 6023    Accepted Submission(s): 2846 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y…

The Solutions of Nonlinear Equation 本文主要介绍几种用于解非线性方程$f(x)=0$的一些方法. (1) Bisection Method. 算法: step 1: 初始化$a,b(b>a)$,使$f(a),f(b)$异号. step 2: while (停止条件不满足) $p=a+\frac{b-a}{2}$: 若 $f(p)f(a)<0$,$b=p$:否则$a=p$. end while step 3: 返回的$p$为方程$f(x)=0$的解. 停止条件…

package com.Amazon.interview; /** * @Author: weblee * @Email: likaiweb@163.com * @Blog: http://www.cnblogs.com/lkzf/ * @Time: 2014年10月25日下午5:14:33 * ************* function description *************** * * Question: * * Given an array with positive int…

Equation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 92    Accepted Submission(s): 24 Problem Description Little Ruins is a studious boy, recently he learned addition operation! He was rewa…

Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12766    Accepted Submission(s): 5696 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y…

I was going through the Coursera "Machine Learning" course, and in the section on multivariate linear regression something caught my eye. Andrew Ng presented the Normal Equation as an analytical solution to the linear regression problem with a l…

Fabricate equation Time Limit: 3000/1000MS (Java/Others)     Memory Limit: 65535/65535KB (Java/Others) Submit Status Given an integer YY, you need to find the minimal integer KK so that there exists a XX satisfying X−Y=Z(Z≥0)X−Y=Z(Z≥0) and the number…

C Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice FZU 2102 Description You are given two positive integers A and B in Base C. For the equation: A=k*B+d We know there always existing many non-negativ…

Can you solve this equation? Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 61   Accepted Submission(s) : 37 Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can y…

10399: F.Turing equation Time Limit: 1 Sec  Memory Limit: 128 MB Submit: 151  Solved: 84 [Submit][Status][Web Board] Description The fight goes on, whether to store  numbers starting with their most significant digit or their least  significant digit…

题目链接:fzu 1909 An Equation 典型的签到题. #include <stdio.h> #include <string.h> bool judge(int *a, int sum) { for (int i = 0; i < 4; i++) { for (int j = i + 1; j < 4; j++) if (sum == (a[i] + a[j]) * 2) return true; } return false; } int main ()…

DP: DP[len][k][i][j] 再第len位,第一个数len位为i,第二个数len位为j,和的第len位为k 每一位能够从后面一位转移过来,能够进位也能够不进位 A Famous Equation Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 500    Accepted Submission(s): 147 Proble…

引言: Normal Equation 是最基础的最小二乘方法.在Andrew Ng的课程中给出了矩阵推到形式,本文将重点提供几种推导方式以便于全方位帮助Machine Learning用户学习. Notations: RSS(Residual Sum Squared error):残差平方和 β:参数列向量 X:N×p 矩阵,每行是输入的样本向量 y:标签列向量,即目标列向量 Method 1. 向量投影在特征纬度(Vector Projection onto the Column Space…

Problem Description Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100; Now please try your lucky. Input The first line of the input contains an integer T(1<=T<=100) which means the number of test…