大致题意:用{ key:value, key:value, key:value }的形式表示一个字典key表示建,在一个字典内没有重复,value则可能重复 题目输入两个字典,如{a:3,b:4,c:10,f:16}  {a:3,c:5,d:10,ee:4} 于新字典相比,找出旧字典的不同,并且输出用相应格式,增加的用'+',如 +d,ee 减少的用'-',如 -b,f value变化的用*,如 *c 没有不同则输出"No changes"" 如果使用java,则可以用Tre…

  Updating a Dictionary  In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Each dictionar…

全是字符串相关处理,截取长度等相关操作的练习 AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cctype> #include <cstring> #include <string> #include <sstream> #include <vector> #include <set> #include…

题意:对比新老字典的区别:内容多了.少了还是修改了. 代码:(Accepted,0.000s) //UVa12504 - Updating a Dictionary //#define _XieNaoban_ #include<iostream> #include<sstream> #include<string> #include<vector> #include<map> using namespace std; int T; int mai…

http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1113 1113: Updating a Dictionary Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 491  Solved: 121[Submit][Status][Web Board] Description In this problem, a dictionary is collection of key-value pairs, w…

UVA12504 - Updating a Dictionary 给出两个字符串,以相同的格式表示原字典和更新后的字典.要求找出新字典和旧字典的不同,以规定的格式输出. 算法操作: (1)处理旧字典,将旧字典中的每对关键字及其价值从字典串中截取出来,压入容器中.用做新旧字典对比检索. (2)处理新字典,将新字典中的每对关键字及其价值从字典串中截取出来.对于每个关键字,在容器中检索相同的关键字.若检索不成功,该关键字是新字典新增的,处理存储到相关的串数组中.若检索成功,提取容器中该关键字的价值与新…

Problem C     Updating a Dictionary In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Eac…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 不确定某个map里面是否有某个关键字的时候. 要用find来确定. 如果直接用访问下标的形式去做的话. 会强行给他加一个那个关键字(原来没有). (当然那个关键字的映射为空就是了); [代码] #include <bits/stdc++.h> using namespace std; string s; map<string, string> mmap1, mmap2; vector <string>…

In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionary and a new dictionary, find out what were changed. Each dictionary is formatting as follow…

题目 题目     分析 第一次用stringstream,真TMD的好用     代码 #include <bits/stdc++.h> using namespace std; int main() { int n; cin>>n; getchar();//回车 while(n--) { string s1,s2; getline(cin,s1); getline(cin,s2); for(int i=0;i<s1.length();i++) if(!isalpha(s1…

传送门 Time Limit: 1000MS   Memory Limit: 131072KB   64bit IO Format: %lld & %llu Description In this problem, a dictionary is collection of key-value pairs, where keys are lower-case letters, and values are non-negative integers. Given an old dictionar…

题目链接:http://acm.csu.edu.cn/OnlineJudge/problem.php?id=1113 解题报告:输入两个字符串,第一个是原来的字典,第二个是新字典,字典中的元素的格式为一个关键字对应一个值,输入格式如下: {a:3,b:4,c:10,f:6} {a:3,c:5,d:10,ee:4}冒号前面的表示关键字,冒号后面的数字表示值,关键字由小写字母组成.现在让你判断,如果新的字典相对于原来的字典有新增的关键字以以下格式输出 :+key1,key2,....如果新的字典相对…

题目描述: 解题思路: 1.根据:和,获得字符串 2.使用两个map进行比较: #include <iostream> #include <algorithm> #include <string> #include <map> using namespace std; map<string, string>::iterator it; map<]; ]; int main(int argc, char *argv[]) { int t ;…

题目链接:https://vjudge.net/problem/UVA-511 题目翻译摘自<算法禁赛入门经典> 题目大意 有 n 张地图(已知名称和某两个对角线端点的坐标)和 m 个地名(已知名称和坐标), 还有 q 个查询.每张地图都是边平行于坐标轴的矩形,比例定义为高度除以宽度的值.每个查询包含一个地名和详细等级 i.面积相同的地图总是属于同一个详细等级.假定包含此地名的地图中一共有 k 种不同的面积,则合法的详细等级为 1-k(其中 1 最不详细,k 最详细, 面积越小越详细).如果详…

A 三家人 Description 有三户人家共拥有一座花园,每户人家的太太均需帮忙整理花园.A 太太工作了5 天,B 太太则工作了4 天,才将花园整理完毕.C 太太因为正身怀六甲无法加入她们的行列,便出了90元.请问这笔钱如何分给A.B 二位太太较为恰当?A 应得多少元?90/(5+4)*5=$50 元?如果这么想你就上当了!正确答案是60 元.如果没想通的话再想想吧. 下面回答一个一般性的问题:假定A 太太工作了x 天,B 太太工作了y 天,C 太太出了90元,则A 太太应得多少元?输入保证…

一.前言 今天事不是很多,正好在Java交流群里,看到一个比较有意思的问题,于是花了点时间研究了一下,这里做个简单的分享. 先贴一份测试代码,大家可以先猜测一下,执行结果会是怎样的: import java.util.concurrent.TimeUnit; public class TestClassLoading { public static class A{ static { System.out.println("class A init"); try { TimeUnit.…

题目链接:uva 1519 - Dictionary Size 题目大意:给出n个字符串组成的字典.如今要加入新的单词,从已有单词中选出非空前缀和非空后缀,组成新单词. 问说能组成多少个单词. 解题思路:建立一棵前缀树和一棵后缀树.有多少节点即为有多少个前缀.扣除中间的部分就可以加上长度为1的字符串就可以. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; con…

感觉这道题要比之前几个字符串处理的题目难度要大了一些. 题目大意:给若干行字符串,提取出所有单词并去掉重复的,最后按字典顺序输出. 对于输入大致有两种思路,一种是逐个读入字符,遇到字母的话就放到word里面,直到遇到非字母字符,在word最后放'\0'. 我采用第二种思路,就是用gets()函数逐行读到str字符数组里面,然后逐个把单词提取出来. Count存放的是Dictionary里单词的个数,每提取一个单词,看看Dictionary里有没有该单词,没有的话放到字典里面,并且计数器加1. 由…

Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. From his book…

Description Andy, , has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. Fr…

Description Andy, , has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. Fr…

Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. From his book…

Problem B: Andy's First Dictionary Time limit: 3 seconds Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all…

Andy's First Dictionary Description 不提英文了 直接上中文大意吧 XY学长刚刚立下了再不过CET就直播xx的flag,为了不真的开启直播模式,XY学长决定好好学习英语.于是他每天都读一篇只包含生词的英语文章,并以自己高达450的智商在一秒钟之内记忆下来. 现在给你一篇XY学长今天要读的文章,请你写一个程序,输出他都学习到了哪些单词.要求:如果文章中有相同的单词,那么仅仅输出一次:而且如果两个单词只有大小写不同,将他们视为相同的单词. Input 测试数据将输入…

  Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. From his bo…

原题链接: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1756 这道题用STL解答还是比较简单的,下面就给大家分享用 set 和 map 的 AC . 解法一(map): #include <iostream> #include <string> #include <map> using names…

题目链接 题意:输入一个文本,找出所有不同的单词(连续的字母序列),按字典序从小到大输出.单词不区分大小写. 刘汝佳算法竞赛入门经典(第二版)P112 #include <iostream> #include <string> #include <set> #include <sstream> using namespace std; set<string> dict;//string集合 int main() { string s,buf; w…

题目链接:https://vjudge.net/contest/211547#problem/C 题目大意: 输入一个文本,找出所有不同的单词(连续的字母序列),按字典序从小到大输出,单词不区分大小写. Sample Input Adventures in Disneyland Two blondes were going to Disneyland when they came to a fork in the road. The sign read: "Disneyland Left.&qu…

题意:给出一段英文,里面包含一些单词,空格和标点,单词不区分大小写,默认都为小写.按照字典序输出这些单词(这些单词不能有重复,字母全部变成小写) stringstream:包含在头文件#include<sstream>中,能将一个字符串分割,用>>输出某些元素 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include…

参考:https://www.cnblogs.com/yjlblog/p/6947747.html https://blog.csdn.net/hnust_taoshiqian/article/details/43448793 https://blog.csdn.net/liuke19950717/article/details/49450817 https://blog.csdn.net/fanyun_01/article/details/66967710 #include <iostream…