Catch That Cow(BFS)】的更多相关文章

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2717 Catch That Cow Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 12615    Accepted Submission(s): 3902 Problem Description Farmer John has been…
传送门 Catch That Cow Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 80273   Accepted: 25290 Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 10…
Catch That Cow Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer…
Catch That Cow Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10166    Accepted Submission(s): 3179 Problem Description Farmer John has been informed of the location of a fugitive cow and wants…
本文来源于:http://blog.csdn.net/svitter 意甲冠军:给你一个数字n, 一个数字k.分别代表主人的位置和奶牛的位置,主任能够移动的方案有x+1, x-1, 2*x.求主人找到奶牛的时间(奶牛不移动) 题解:最基础的BFS可是脑子犯抽WA了3遍- = 注意: 1.数组范围1~1<<5 2.visit去重.(BFS最基础的) 代码: #include <iostream> #include <stdio.h> #include <string…
Catch That Cow Time Limit : 4000/2000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 67   Accepted Submission(s) : 22 Problem Description Farmer John has been informed of the location of a fugitive cow and wants to c…
Catch That Cow bfs代码 #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<string> #include<vector> #include<stack> #include<bitset> #include<cstdlib> #include<cmath>…
Catch That Cow Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9753    Accepted Submission(s): 3054 Problem Description Farmer John has been informed of the location of a fugitive cow and wants…
Problem Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. F…
题目:http://poj.org/problem?id=3278 题意: 给定两个整数n和k 通过 n+1或n-1 或n*2 这3种操作,使得n==k 输出最少的操作次数 #include<stdio.h> #include<string.h> #include<queue> using namespace std; ]; struct node { int x,step; }; int bfs(int n,int k) { if(n==k) ; queue<n…