How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17946    Accepted Submission(s): 8822 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinn…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 简单的并查集 代码: #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #define maxn 1100 using namespace std; int parent[maxn]; int m,n; int Find(int x) { int s; ;s=pa…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other,…

Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay with strang…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the frie…

题解:1 2,2 3,4 5,是朋友,所以可以坐一起,求最小的桌子数,那就是2个,因为1 2 3坐一桌,4 5坐一桌.简单的并查集应用,但注意题意是从1到n的,所以要减1. 代码: #include <map> #include <set> #include <list> #include <cmath> #include <queue> #include <stack> #include <vector> #includ…

并查集基本知识看:http://blog.csdn.net/dellaserss/article/details/7724401 题意:假设一张桌子可坐无限多人,小明准备邀请一些朋友来,所有有关系的朋友都可以坐同一张桌,没有关系的则要另开一桌,问需要多少张桌子(小明不坐,不考虑小明与其他人的关系)? 思路:常规的并查集.要求出所有人的老大,有几个老大就要几张桌子.那么有关系的都归为同一个老大.用数组实现,再顺便压缩路径. #include <bits/stdc++.h> #define LL…

题目大意:有n个人 m行数据,每行数据给出两个数A B,代表A-B认识,如果A-B B-C认识则A-C认识,认识的人可以做一个桌子,问最少需要多少个桌子. 题目思路:利用并查集对相互认识的人进行集合的划分,划分完毕后进行遍历,如果发现一个点的根节点是本身,证明找到一个集合,统计集合数便是答案了. #include<cstdio> #include<cstdlib> #include<cmath> #include<iostream> #include<…

http://acm.hdu.edu.cn/showproblem.php?pid=1213 果然是需要我陪跑T T,禽兽工作人员还不让,哼,但还是陪跑了~ 啊,还有呀,明天校运会终于不用去了~耶耶耶,又可以快乐的玩耍了~ 水一题睡觉~ ------------------------------------------------华丽的分割线------------------------------------------------- 大意: XXX过生日,他要请客.请客的座位安排是认识的…

题目地址 http://acm.hdu.edu.cn/showproblem.php?pid=1213 #include<iostream> using namespace std; #define MAX 100005 int fa[MAX]; int findHead(int x) { while(x!=fa[x]) x=fa[x]; return x; } void Union(int x,int y) { int fa_x=findHead(x); int fa_y=findHead(…

F - How Many Tables 并查集的模板都能直接套,太简单不注释了,就存个代码 #include<bits/stdc++.h> using namespace std; ; int parent[size]; ]; int t, n, m, x, y, num; //赋初值 void parentkey(int n){ ;i<=n;i++){ parent[i] = i; cnt[i] = ; } } //找根节点 int find(int x){ return x==par…

这道题跟HDU 1213 How Many Tables 并查集很接近,都是赤裸裸的并查集的题. 思路:如果还须要建n-1条路.每并一次就自减1. 參考代码: #include<stdio.h> int fa[1000]; int find(int u) { return fa[u]==u? u:fa[u]=find(fa[u]); } int main() { int i,n,m,u,v,x,y; scanf("%d%d",&n,&m); while (n…

How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 46694    Accepted Submission(s): 23319 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Description: Today is Ignatius' birthda…

题目大意: 有一个人要过生日了,请他的朋友来吃饭,但是他的朋友互相认识的才能坐在一起,朋友的编号从1 ~ n,输入的两个数代表着这两个人互相认识(如果1和2认识,2和3认识,那么1和3也就认识了).问需要多少桌子. 思路: 并查集的基础题目,pre数组存的是父节点的值,root数组代表是否为根节点.最后统计根节点的数量就可以了~~~~~ #include <iostream> #include <cstdio> #include <cstring> #include &…

-----------刷点水题练习java------------- 题意:给定N点,M边的无向图,问有多少个连通块. 思路:可以搜索;  可以并查集.这里用并查集练习java的数组使用,ans=N,合并一个连通块ans--: 以及函数的调用: 经验1:C++声明数组是int fa[1024]:而java则是int[] fa=new int[1024]; 经验2:不加static是非静态函数,访问需要new出该类的对象来调用,加上static是静态函数 可直接访问或者通过类名访问. import…

How Many Tables 题目链接: http://acm.hust.edu.cn/vjudge/contest/123393#problem/C Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that…

题目链接:hdu1213 赤裸裸的并查集.....水题一个.... #include<stdio.h> #include<string.h> #include<algorithm> #include<queue> #define MAXN 10 using namespace std; int father[1005]; void build(int n) { for(int i = 0 ; i <= n ; i ++) father[i] = i;…

题目传送门:HDU--1213 //题意:ignatius过生日,客人来到,他想知道他需要准备多少张桌子.然而一张桌子上面只能坐上相互熟悉的人, //其中熟悉可定义成为A与B认识,B与C认识,我们就说A,B,C相互熟悉 .例如A与B熟悉and B与C熟悉,D与E熟悉,此时至少需要两张桌子. //输入:t表示样例个数,n表示朋友个数,朋友从1到n编号,m表示已知相互了解的对数,接着m行.每行表示相互熟悉的编号 //输出:至少需要准备的桌子个数 //刚学并查集!简单的并查集模板应用. #includ…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1213 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the fri…

How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 14081    Accepted Submission(s): 6912 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinn…

传送门:How Many Tables 模板代入 判断几个连通分支 DFS亦可完成 [并查集] #include <iostream> #include <cstdio> #include <algorithm> using namespace std; const int maxn = 50005; int n,m; int a,b,ans; int pre[maxn]; void init() { for(int i=1;i<=n;i++) pre[i] =…

How Many Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 31632 Accepted Submission(s): 15706 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner ti…

J - How Many Tables Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You…

Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay…

How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at…

并查集的经典题目. 并查集.经典题目是HDU1232通畅工程. 题目描述: 某省调查城镇交通状况,得到现有城镇道路统计表,表中列出了每条道路直接连通的城镇.省政府"畅通工程"的目标是使全省任何两个城镇间都可以实现交通(但不一定有直接的道路相连,只要互相间接通过道路可达即可).问最少还需要建设多少条道路? Output: 对每个测试用例,在1行里输出最少还需要建设的道路数目. Sample Input: 测试输入包含若干测试用例.每个测试用例的第1行给出两个正整数,分别是城镇数目N (…

题目链接:http://icpc.njust.edu.cn/Problem/Hdu/1213/ 并查集是一种支持合并与查找的数据结构,在森林中进行操作,加上路径压缩,合并和查找的时间复杂度几乎都是常数.并查集最基础的作用就是建立不同的点之间的所谓的“关系”,并且查询两者是否有关系.并查集的一个特点是向量型关系传递性,比如A->B B->C,则有A->C,是不是特别像向量之间的传递?在很多时候并查集的应用都涉及到了这个性质.并查集的代码可比线段树主席树友好一点orz hdu1213板题,代…

定义&&概念: 啥是并查集,就是将所有有相关性的元素放在一个集合里面,整体形成一个树型结构,它支持合并操作,但却不支持删除操作 实现步骤:(1)初始化,将所有节点的父亲节点都设置为自己,例如pre[1]=1(2)合并,将一个元素或者一集合(两者间有联系)合并到另外一个集合(元素)里面,谁是谁的父亲节点不需要过多在意,视题意而定.(3)查找,在合并时需要运用到查找操作,即查找该元素的父节点,尽量使用路径压缩,可以使并查集更加高效,一旦使用了路径压缩,查询时就会将该查询元素到父亲的边改为直接连…

HDU1213How Many Tables Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all…

题意:有 n 个朋友,他们可能相互认识,A 认识 B,B 认识 C,则 ABC 相互认识,现在给出他们的认识情况,相互认识的人坐一桌,否则需要分开坐,问至少需要多少桌. 其实就是问并查集的个数,在初始情况下一人一个并查集,共 n 个,每次合并操作会减少一个并查集,所以只要每次合并时计数减一下就行,全部合并完之后就可以输出剩余并查集个数了. #include<iostream> #include<cstdio> #include<cstring> using namesp…