执行hdfs namenode -bootstrapStandby的时候报错如下 19/03/24 18:00:48 ERROR namenode.NameNode: Failed to start namenode.java.io.IOException: java.lang.IllegalStateException: Could not determine own NN ID in namespace 'mycluster'. Please ensure that this node is…

c++ anonymous namespace -- 匿名空间 匿名空间,匿名类,匿名联合体,匿名结构体.   匿名空间   #include <stdio.h> namespace A { int ID = 1; } namespace { int ID = 11; } namespace B { int ID = 21; } int main(void){ printf("ID %d \n",ID); } 输出 ID 11 这里用到是C的函数,减少std空间的干扰.这里…

UNIX进程总是会分配一个号码用于在其命名空间总唯一地标识它们,该号码称作进程ID号,简称PID. 1.进程ID 但每个进程除了PID外,还有其他的ID,有下列几种可能的类型: (1)处于某个线程组中的所有进程都有统一的线程组ID(TGID).若进程没有使用线程,则其PID和TGID相同.线程组中主进程被称作组长(group leader).通过clone创建的所有线程的task_struct的group_leader成员,会指向组长task_struct实例. (2)独立进程可以合并为进程组(…

This document is a starting point for users working with Hadoop Distributed File System (HDFS) either as a part of a Hadoop cluster or as a stand-alone general purpose distributed file system. While HDFS is designed to "just work" in many enviro…

codevs1022 覆盖 有一个N×M的单位方格中,其中有些方格是水塘,其他方格是陆地.如果要用1×2的矩阵区覆盖(覆盖过程不容许有任何部分重叠)这个陆地,那么最多可以覆盖多少陆地面积. 输入描述 Input Description 输入文件的第一行是两个整数N,M  (1<=N,M<=100),第二行为一个整数K( K<=50),接下来的K行,每行两个整数X,Y表示K个水塘的行列位置.(1<=X<=N,1<=Y<=M). 输出描述 Output Descrip…

http://poj.org/problem?id=2886 单点更新 初始位置都是1 如果这个人出去 位置变为0 利用线段树求区间k值 k值的计算如下 如果这个数值是负的 那么下一个人的就是((k-1+p[id].d)%n+n)%n+1; 如果是正的 下一个人就是(k-1+p[id].d-1)%n+1; #include <cstdio> #include <cstring> #include <algorithm> #include<stdlib.h>…

HDFS Users Guide Purpose Overview Prerequisites Web Interface Shell Commands DFSAdmin Command Secondary NameNode Checkpoint Node Backup Node Import Checkpoint Rebalancer Rack Awareness Safemode fsck fetchdt Recovery Mode Upgrade and Rollback File Per…

Files and Directories Introduction     In the previous chapter we coveredthe basic functions that perform I/O. The discussion centered on I/O for regular files-opening a file, and reading or writing a file. We'll now look at additionalfeatures of the…

# Copyright 2001-2016 by Vinay Sajip. All Rights Reserved. # # Permission to use, copy, modify, and distribute this software and its # documentation for any purpose and without fee is hereby granted, # provided that the above copyright notice appear…

转自:http://blog.csdn.net/tutucute0000/article/details/39756123 从nameNode1.namenode2克隆出namenode3.namenode4,分别作为1.2的standby node. 把datanode2.3.4作为namenode1的jounalnodes,datanode4.5.6作为namenode2的journalnodes. 同时将datanode2.3.4组成zookeeper cluster1,datanode5…