欢迎访问~原文出处——博客园-zhouzhendong 去博客园看该题解 题目传送门 - HDU1711 题意概括 给T组数据,每组有长度为n和m的母串和模式串.判断模式串是否是母串的子串,如果是输出最先匹配完成的位置,否则输出-1. 题解 KMP裸题. 代码 #include <cstring> #include <algorithm> #include <cstdio> #include <cstdlib> #include <cmath>…

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1711 题目: Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which m…

题目传送门 学习博客 学习了kmp算法,理解了算法思想,但还没有到能把这个思想用语言来描述出来. #include<bits/stdc++.h> #define clr(a,b) memset(a,b,sizeof(a)) using namespace std; typedef long long ll; ; int a[maxn],b[maxn],f[maxn]; int n,m; void fail(){ f[]=-; ;j<m;j++) { ];;i=f[i]){ ]){ f[j…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 40053    Accepted Submission(s): 16510 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 27028    Accepted Submission(s): 11408 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11691    Accepted Submission(s): 5336 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ......…

Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1] = b[M]. If there are…

题意 找到子串在母串出现的第一个位置 解法 裸的KMP 特别的地方 第一次不看模板自己敲的KMP #include<stdio.h> const int maxn=100000; const int MAXN=1000000; int next[maxn]; int S[MAXN]; int T[maxn]; int N,M; void get_next() { for(int i=2;i<=M;i++) { int p=i-1; while(T[next[p]+1]!=T[i]&…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 题目大意:最基础的字符串匹配,只不过这里用整数数组代替了字符串. 给你两个数组 \(a[1..N]\) 和 \(b[1..M]\) ,找到最小的 \(K\) 使得 \(a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1] = b[M]\) . 题目分析:就是最基础的KMP字符串匹配,改一下数据类型. 实现代码如下: #include <cstd…