You are given two positive integer numbers a and b. Permute (change order) of the digits of a to construct maximal number not exceeding b. No number in input and/or output can start with the digit 0. It is allowed to leave a as it is. Input The first…

思路: 从左到右贪心放置数字,要注意判断这个数字能否放置在当前位. 实现: #include <bits/stdc++.h> using namespace std; typedef long long ll; ], buf[]; bool check(ll t, ll b) { memcpy(buf, cnt, ); ; i <= ; i++) { ; t += i; buf[i]--; } } return t <= b; } int main() { string a, b;…

题目链接:Permute Digits 题意: 给出了两个数字a,b(<=1e18),保证a,b都不带前缀0.用a的字符重组一个数字使这个值最大且小于b.(保证这个值存在) 题解: 这题遇到了不止一遍了,但是每次都会写错-所以感觉很有必要写下来.看到这题,我的第一想法是贪心每次都取最大的.但是这样其实存在很大的漏洞,因为字符个数是有限的如果小的数被取完了大的数填充进去也不符合条件.这题要按DFS的思路去做才行.这里给出按贪心的做法的一组错误数据. a: 123456789123456789 b:…

C. Permute Digits time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given two positive integer numbers a and b. Permute (change order) of the digits of a to construct maximal number n…

C. Permute Digits You are given two positive integer numbers a and b. Permute (change order) of the digits of a to construct maximal number not exceeding b. No number in input and/or output can start with the digit 0. It is allowed to leave a as it i…

Given Length and Sum of Digits... 题目链接: http://acm.hust.edu.cn/vjudge/contest/121332#problem/F Description You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m…

You are given two positive integer numbers a and b. Permute (change order) of the digits of a to construct maximal number not exceeding b. No number in input and/or output can start with the digit 0. It is allowed to leave a as it is. Input The first…

You are given two positive integer numbers a and b. Permute (change order) of the digits of a to construct maximal number not exceeding b. No number in input and/or output can start with the digit 0. It is allowed to leave a as it is. Input The first…

You are given two positive integer numbers a and b. Permute (change order) of the digits of a to construct maximal number not exceeding b. No number in input and/or output can start with the digit 0. It is allowed to leave a as it is. Input The first…

https://cn.vjudge.net/problem/UVA-1368 二维的hamming距离算法: For binary strings a and b the Hamming distance is equal to the number of ones (population count) in a XOR b. int hamming_distance(unsigned x, unsigned y) { ; unsigned val = x ^ y; // Count the n…