http://poj.org/problem?id=1655 (题目链接) 题意 给出一棵树,求树上一点使得使得删除一点后该树的最大子树最小. solution 树的重心裸题. 随意取一点作为根节点,dfs维护当前节点的最大子树大小以及它的父亲子树大小,更新答案. 代码 // poj1655 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include&…

[题目链接] 点击打开链接 [算法] 树形DP求树的重心 [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #include <cstdlib>…

Balancing Act Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 14251   Accepted: 6027 Description Consider a tree T with N (1 <= N <= 20,000) nodes numbered 1...N. Deleting any node from the tree yields a forest: a collection of one or m…

poj 1655 Balancing Act 题意:求树的重心且编号数最小 一棵树的重心是指一个结点u,去掉它后剩下的子树结点数最少. (图片来源: PatrickZhou 感谢博主) 看上面的图就好明白了,不仅要考虑当前结点子树的大小,也要“向上”考虑树的大小. 那么其它就dfs完成就行了,son[] 存以前结点为根的结点个数. 这是用邻接表写: #include<iostream> #include<cstdio> #include<cstring> #includ…

http://poj.org/problem? id=1655 Balancing Act Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9072   Accepted: 3765 Description Consider a tree T with N (1 <= N <= 20,000) nodes numbered 1...N. Deleting any node from the tree yields a f…

题目链接 Balancing Act 就是求一棵树的重心,然后统计答案. #include <bits/stdc++.h> using namespace std; #define REP(i,n) for(int i(0); i < (n); ++i) #define for_edge(i,x) for(int i = H[x]; i; i = X[i]) const int INF = 1 << 30; const int N = 100000 + 10; int H[N…

题目链接: Balancing Act Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11845   Accepted: 4993 Description Consider a tree T with N (1 <= N <= 20,000) nodes numbered 1...N. Deleting any node from the tree yields a forest: a collection of on…

Balancing Act Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 14247   Accepted: 6026 Description Consider a tree T with N (1 <= N <= 20,000) nodes numbered 1...N. Deleting any node from the tree yields a forest: a collection of one or m…

Balancing Act Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12703   Accepted: 5403 Description Consider a tree T with N (1 <= N <= 20,000) nodes numbered 1...N. Deleting any node from the tree yields a forest: a collection of one or m…

[导读]TensorFlow 在 2015 年年底一出现就受到了极大的关注,经过一年多的发展,已经成为了在机器学习.深度学习项目中最受欢迎的框架之一.自发布以来,TensorFlow 不断在完善并增加新功能,直到在这次大会上发布了稳定版本的 TensorFlow V1.0.这次是谷歌第一次举办的TensorFlow开发者和爱好者大会,我们从主题演讲.有趣应用.技术生态.移动端和嵌入式应用多方面总结这次大会上的Submit,希望能对TensorFlow开发者有所帮助. TensorFlow:面向大…