题意: Determine whether an integer is a palindrome. Do this without extra space.  (Easy) 分析: 自己考虑的方法是利用Reverse Integer,然后查看rev与x是否相等,注意负数和0的判断(这里WA了一次) 代码1: class Solution { private: int reverse(int x) { ; ) { ; x /= ; result = result * + temp; if (res…

题目描述 Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation: From left to right, it reads -121. From rig…

Reverse Integer Reverse digits of an integer. Example1: x =  123, return  321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have alr…

文章转自http://blog.163.com/hljmdjlln@126/blog/static/5473620620120412525181/ 做LC上的题"Palindrome number"时翻到此文章,经过少量修改后如下. 回文数是数学界中的一种有趣的现象.比如121就是一个回文数.回文数的数字互相对应,从中间一个任意一位数字起,左右每隔一个的数字都相等.回文数有许多神奇的规律和奥秘.主要分为读数回文数.平方回文数.乘积回文数以及倒乘回文数. 一.读数回文数 [解释]读数回文…

/* Determine whether an integer is a palindrome. Do this without extra space. click to show spoilers. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using…

9. Palindrome Number Total Accepted: 136330 Total Submissions: 418995 Difficulty: Easy Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of conv…

9 - Palindrome Number Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra…

Palindrome Number time=434ms 负数不是回文数 public class Solution { public boolean isPalindrome(int x) { int palindrome=0; int revers=x; if(revers<0) return false; else{ while(revers>0){ int m=revers%10; palindrome=m+palindrome*10; revers=revers/10; } if(p…

主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5062 Problem Description A positive integer x can represent as (a1a2-akak-a2a1)10 or (a1a2-ak−1akak−1-a2a1)10 of a 10-based notational system, we always call x is a Palindrome Number. If it satisfies 0<…

第一个题目是将整数进行反转,这个题实现反转并不难,主要关键点在于如何进行溢出判断.溢出判断再上一篇字符串转整数中已有介绍,本题采用其中的第三种方法,将数字转为字符串,使用字符串比较大小的方法进行比较. 代码如下: class Solution { public: int reverse(int x) { ]={,,,,,,,,,}; ]; ,flag=; ) flag=; else ) { flag=-; x=-x; } else ; ; ) { getnum[count]=(x%); x=x/…