Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…

Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…

Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…

Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. No…

题目如下: Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original B…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/insert-into-a-binary-search-tree/description/ 题目描述 Given the root node of a binary search tree (BST) and a value to be inserted into the t…

1.题目描述 2.分析 插入算法. 3.代码 TreeNode* insertIntoBST(TreeNode* root, int val) { insert(root, val); return root; } void insert(TreeNode * & t , int val) { if (t == NULL) t = new TreeNode(val); else if (val < t->val) { insert(t->left, val); } else if…

https://www.cnblogs.com/grandyang/p/9914546.html 类似于二分查找的方法,用迭代的方法去做 注意:无论是进入左子树还是右子树,左右子树都变成了新的数,所以需要重新根据root->left = ....来重新生成 class Solution { public: TreeNode* insertIntoBST(TreeNode* root, int val) { if(root == NULL) return new TreeNode(val); if…

Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For exampl…

二叉查找树基础 二叉查找树(BST)满足这样的性质,或是一颗空树:或左子树节点值小于根节点值.右子树节点值大于根节点值,左右子树也分别满足这个性质. 利用这个性质,可以迭代(iterative)或递归(recursive)地用O(lgN)的时间复杂度在二叉查找树中进行值查找. 相关LeetCode题: 700. Search in a Binary Search Tree  题解 701. Insert into a Binary Search Tree  题解 450. Delete Node…