HZAU 1199: Little Red Riding Hood 01背包】的更多相关文章

题目链接:1199: Little Red Riding Hood 思路:dp(i)表示前i朵花能取得的最大价值,每一朵花有两种选择,摘与不摘,摘了第i朵花后第i-k到i+k的花全部枯萎,那么摘的话dp(i) = dp(i-k-1) + a[i],不摘就是dp(i) = dp(i-1),因此转移方程就是dp(i) = max(dp(i-k-1) + a[i], dp(i-1)). AC代码 #include <cstdio> #include <cmath> #include &l…
1199: Little Red Riding Hood Time Limit: 1 Sec  Memory Limit: 1280 MBSubmit: 918  Solved: 158[Submit][Status][Web Board] Description Once upon a time, there was a little girl. Her name was Little Red Riding Hood. One day, her grandma was ill. Little…
Little Red Riding Hood Time Limit: 1 Sec  Memory Limit: 1280 MBSubmit: 853  Solved: 129[Submit][Status][Web Board] Description Once upon a time, there was a little girl. Her name was Little Red Riding Hood. One day, her grandma was ill. Little Red Ri…
问题 : Little Red Riding Hood 时间限制: 1 Sec  内存限制: 1280 MB 题目描述 Once upon a time, there was a little girl. Her name was Little Red Riding Hood. One day, her grandma was ill. Little Red Riding Hood went to visit her. On the way, she met a big wolf. "That'…
Washing Clothes Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 9707   Accepted: 3114 Description Dearboy was so busy recently that now he has piles of clothes to wash. Luckily, he has a beautiful and hard-working girlfriend to help him…
劲歌金曲 [题目链接]劲歌金曲 [题目类型]01背包 &题解: 题意:求在给定时间内,最多能唱多少歌曲,在最多歌曲的情况下,使唱的时间最长. 该题类似于01背包问题,可用01背包问题的解题思路来求,每个歌曲相当于物品,歌曲的长度相等于物品重量,每个歌曲的"价值"为1.由于金歌劲曲时间最长,所以最后要留至少1秒时间开始唱金歌劲曲,所以计算t-1时间内最多唱的歌曲和时间,最终答案为歌曲数加1,时间加上金歌劲曲的时间.这里我使用滚动数组计算这个值, 用len记录t-1. 需要注意的是…
Washing Clothes Time Limit: 1000MS Memory Limit: 131072K Total Submissions: 9700 Accepted: 3110 Description Dearboy was so busy recently that now he has piles of clothes to wash. Luckily, he has a beautiful and hard-working girlfriend to help him. Th…
Q: 01背包最后返回什么 dp[v], v 是多少? A: 普通01背包需要遍历, 从大到小. 但此题因为物品的总重量必定大于背包容量, 所以直接返回 dp[V] 即可 update 2014年3月14日11:22:55 1. 几个月后, 感觉返回的不应该是 dp[V], 二是 dp[0...V] 中的最大值 Description Dearboy was so busy recently that now he has piles of clothes to wash. Luckily, h…
Washing Clothes Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 9384   Accepted: 2997 Description Dearboy was so busy recently that now he has piles of clothes to wash. Luckily, he has a beautiful and hard-working girlfriend to help him…
题目链接: id=3211">poj3211  hdu1171 这个题目比1711难处理的是字符串怎样处理,所以我们要想办法,自然而然就要想到用结构体存储.所以最后将全部的衣服分组,然后将每组时间减半,看最多能装多少.最后求最大值.那么就非常愉快的转化成了一个01背包问题了... . hdu1711是说两个得到的价值要尽可能的相等.所以还是把全部的价值分为两半.最后01背包,那么这个问题就得到了解决.. 题目: Washing Clothes Time Limit: 1000MS   Me…