Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 判断两棵树是否相同和之前的判断两棵树是否对称都是一样的原理,利用深度优先搜索DFS来递归.代码如下: 解法一: class Solu…

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following is not: 1 / \ 2 2 \ \ 3 3 Note:Bonus points if you could solve it b…

Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 二叉树相同:一.结构相同:二.对应节点上的值相同. 思路:层次遍历,维护两个队列,判断对应节点的值是否相等.值得注意的有:一.节点均…

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree [1,2,2,3,4,4,3] is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following [1,2,2,null,3,null,3] is not: / \ \ \ Note:Bonus po…

Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following is not: 1 / \ 2 2 \ \ 3 3 Note:Bonus points if you could solve it b…

题意:如题 思路:递归解决,同判断对称树的原理差不多.先保证当前两个结点是相等的,再递归保证两左结点是相等的,再递归保证右结点是相等的. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Sol…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:先序遍历 方法二:DFS + DFS 方法三:BFS + DFS 日期 题目地址:https://leetcode.com/problems/subtree-of-another-tree/#/description 题目描述 Given two non-empty binary trees s and t, check whether tr…

方法1:  $('#domaincatalog').tree('isLeaf', node.target); 返回true或false ,true表示是叶节点, false即不是 方法2:官方文档中:看到每个节点都有一些属性,其中一个是state,我们就通过这个state来判断.state有两个值 open和closed表示当前节点 打开和关闭了树的状态.当state等于undefined的时候就表示当前节点是Leaf 叶了. 在tree的onclick事件上添加判断代码如下 $("#domai…

LeetCode: Binary Tree Traversal 题目:树的先序和后序. 后序地址:https://oj.leetcode.com/problems/binary-tree-postorder-traversal/ 先序地址:https://oj.leetcode.com/problems/binary-tree-preorder-traversal/ 后序算法:利用栈的非递归算法.初始时,先从根节点一直往左走到底,并把相应的元素进栈:在循环里每次都取出栈顶元素,如果该栈顶元素的右…

[试题描述]定义一个函数,输入判断一个树是否是另一个对的子树 You have two very large binary trees: T1, with millions of nodes, and T2, with hun-dreds of nodes Create an algorithm to decide if T2 is a subtree of T1 Note that the problem here specifies that T1 has millions of nodes…