1025 PAT Ranking (25分) 1. 题目 2. 思路 设置结构体, 先对每一个local排序,再整合后排序 3. 注意点 整体排序时注意如果分数相同的情况下还要按照编号排序 4. 代码 #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> using namespace std; struct stu{ int location_number; char…

PAT甲级:1025 PAT Ranking (25分) 题干 Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged imme…

题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1025 题目描述: Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the…

题目如下: Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. No…

problem Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test.…

Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it i…

题目 Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now i…

题意: 给定一次PAT测试的成绩,要求输出考生的编号,总排名,考场编号以及考场排名. 分析: 题意很简单嘛,一开始上来就,一组组输入,一组组排序并记录组内排名,然后再来个总排序并算总排名,结果发现最后一个测试点超时. 发现自己一开始太傻太盲目,其实只要一次性全部输进来,记录好考场编号,一次排序就可以了.既然只排了一次,怎么计算考场排名呢,这里我用了三个数组 ];//记录各个考场当前排到的名次 (当前最后一个人的名次) ];//记录个考场当前排到的最后一个人的分数 ];//记录个考场当前已经排好队…

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<queue> #include<string> #include<vector> using namespace std; ; ; int sz[maxn]; struct X { string id; i…

排序,求整体的排名和局部的排名整体排序,for循环一遍同时存储整体目前的排名和所在局部的排名即可 #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <queue> #include <map> using namespace std; ; ; int local_R…