Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others) Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in PE. According to the rule, you must keep your speed, and…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=6071 题解 又是一道虐信心的智商题... 首先有一个辅助问题,这道题转化了一波之后就会化成这个问题: 给定\(a_1,a_2,...,a_n\)和\(K\),求使得\(\sum^{n}_{i=1}a_ix_i=B\)有正整数解且\(B\ge K\)的最小\(B\)值.在本题中\(n=4, a_i\le 30000, K\le 10^{18}\). 这好像是个最短路经典问题,但是我想了三小时根本没想到…

/* HDU 6071 - Lazy Running [ 建模,最短路 ] | 2017 Multi-University Training Contest 4 题意: 四个点的环,给定相邻两点距离,问从2号点出发,2号点结束,距离大于k的最短距离 d(i,j) < 30000, k <= 1e18 分析: 设 r = min(d(1,2), d(2,3)) 假设距离 k 可达,则 k+2*r 也可达(来回走的形式) 故求出所有 d[i][j] 满足 d[i][j]%2r == j 的最短距离…

Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 1384    Accepted Submission(s): 597 Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in…

Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 101    Accepted Submission(s): 40 Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in PE…

http://acm.hdu.edu.cn/showproblem.php?pid=6071 题意: 1.2.3.4四个点依次形成一个环,现在有个人从2结点出发,每次可以往它相邻的两个结点跑,求最后回到2结点并且不少于K的最短距离. 思路: 官方题解: 最后的答案可以表示为:$ans=p*(2w)+m$,这样一来,m的取值范围就是$(0<=m<2w)$,而因为m的不同,p值也会有所不同.所以我们用 d [ i ] [ m ]表示从起点出发,最后到达 i 点,距离对2w取模为m时的最小距离,这个…

[题目链接] http://acm.hdu.edu.cn/showproblem.php?pid=6071 [题目大意] 给出四个点1,2,3,4,1和2,2和3,3和4,4和1 之间有路相连, 现在从2点出发,最后回到2点,要求路径大于等于K,问路径长度最短是多少 [题解] 取一条与2相连的权值最小的边w. 若存在一条从起点到终点的长度为k的路径, 那么必然存在一条长度为k+2w的路径,只要一开始在那条边上往返走就好了. 设dij表示从起点到i,路径长度模2w为j时,路径长度的最小值. 用最短…

lazy running(最短路) 题意: 一个环上有四个点,从点2出发回到起点,走过的距离不小于K的最短距离是多少 \(K <= 10^{18} 1 <= d <= 30000\) 看完这道题,觉得这是个智力题,想了一想,无从下手啊 每次总是看完题解,就豁然开朗 其实之前做过一个类似的题,题目 但是根本想不到第一步, 选2w来转换啊,而且也不知道正确性啊 这类题要仔细理解一番 #include<bits/stdc++.h> #define LL long long #def…

Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 657    Accepted Submission(s): 284 Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in P…

地址:http://acm.split.hdu.edu.cn/showproblem.php?pid=6071 题目: Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 144    Accepted Submission(s): 62 Problem Description In HDU, you have…