PostgreSQL按年月日分组】的更多相关文章

Select EXTRACT(year from cast(joindate as timestamp)) as Year, EXTRACT(month from cast(joindate as timestamp)) as Month, EXTRACT(day from cast(joindate as timestamp)) as Day, ...... From Table Group by Year,Month,Day…
Select EXTRACT(year from cast(joindate as timestamp)) as Year, EXTRACT(month from cast(joindate as timestamp)) as Month, EXTRACT(day from cast(joindate as timestamp)) as Day, ...... From Table Group by Year,Month,Day…
Mysql 根据时间戳按年月日分组统计create_time时间格式SELECT DATE_FORMAT(create_time,'%Y%u') weeks,COUNT(id) COUNT FROM role GROUP BY weeks;SELECT DATE_FORMAT(create_time,'%Y%m%d') days,COUNT(id) COUNT FROM role GROUP BY days;SELECT DATE_FORMAT(create_time,'%Y%m') month…
sql server  按年月日分组 ----------------------------------------------- --author:yangjinwang --date:2017-03-30 --do:根据活动查询 每个奖品类的发放数量 ----------------------------------------------- create proc GetWinningInfoTypeCountByTimeActivity @CreateTimeStart dateti…
sql根据时间戳按年月日分组统计,用于按日期分类: create_time为时间格式(字段名create_time 根据自己表字段修改,数据库中存为201610071202) SELECT DATE_FORMAT(create_time,'%Y%u') weeks,COUNT(id) COUNT FROM role GROUP BY weeks; SELECT DATE_FORMAT(create_time,'%Y%m%d') days,COUNT(id) COUNT FROM role GRO…
在写一个统计查询的 SQL 语句时,需要根据年.月.日分组,但要求返回的字段是日期格式:yyyy年MM月dd日.刚开始我的做法是返回年.月.日,然后再手动拼接年月日,而且还要判断月份和日期是否为个位数,是的话需要在左侧补零.项目经理看了我代码之后,告诉我直接可以在 SQL 中处理.下面是 SQL 语句: SELECT CAST(stats_year AS character varying) || '年' || lpad(CAST(stats_month AS character varying…
action(methods=['GET'], detail=False, url_path='count') def count(self, request): """统计最近30天的抓拍记录""" starttime = request.query_params.get('starttime') endtime = request.query_params.get('endtime') days = datetime.timedelta(da…
create_time时间格式 SELECT DATE_FORMAT(create_time,'%Y%u') weeks,COUNT(id) COUNT FROM role GROUP BY weeks; SELECT DATE_FORMAT(create_time,'%Y%m%d') days,COUNT(id) COUNT FROM role GROUP BY days; SELECT DATE_FORMAT(create_time,'%Y%m') months,COUNT(id) COUN…
1.获取当前日期的年份 select to_char(t.detect_date,'YYYY') select extract(year from now())为double precision 格式类型 select to_char((SELECT now()::timestamp),'yyyy') 2.获取下一年 select to_char((SELECT now()::timestamp+ '1 year'),'yyyy') 3.获取上一年 select to_char((SELECT…
create_time时间格式 SELECT DATE_FORMAT(create_time,'%Y%u') weeks,COUNT(id) COUNT FROM role GROUP BY weeks; SELECT DATE_FORMAT(create_time,'%Y%m%d') days,COUNT(id) COUNT FROM role GROUP BY days;         SELECT DATE_FORMAT(create_time,'%Y%m') months,COUNT(…