[array] leetcode-55. Jump Game - Medium】的更多相关文章

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. Example 1: Input…
55. Jump Game Description Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the la…
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55. Jump Game 第一种方法: 只要找到一个方式可以到达,那当前位置就是可以到达的,所以可以break class Solution { public: bool canJump(vector<int>& nums) { int length = nums.size(); ) return false; vector<bool> dp(length,false); dp[] = true; ;i < length;i++){ ;j >= ;j--){…
1. 原题链接 https://leetcode.com/problems/jump-game/description/ 2. 题目要求 给定一个整型数组,数组中没有负数.从第一个元素开始,每个元素的值代表每一次你能从当前位置跳跃的步数.问能否跳到该数组的最后一个元素位置 注意:可以跳的步数超出数组长度依旧视为可以达到最后位置 3. 解题思路 从第一个元素开始遍历,记录下你所能到达的最远位置,例如{2, 2, 0, 1, 2},遍历第一个元素时,你所能到达的最远位置是“i+nums[i]”=2,…
原题 题目意思即 每一格代表你当前最多能再往后跳几次,从第一格开始,如果能跳到最后一格返回true,反之为false. 思路:用一个下标记录当前最多能跳到哪一格,遍历一遍 --> 如果当前格子不在可以跳到的范围内,则跳出遍历 --> 如果最多能跳到格子长度大于数组长度,则为true: /** * @param {number[]} nums * @return {boolean} */ var canJump = function(nums) { var rightIndex = 1; for…
Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position. Determine if you are able to reach the last index. Example 1: Input…
Jump Game 是一道有意思的题目.题意很简单,给你一个数组,数组的每个元素表示你能前进的最大步数,最开始时你在第一个元素所在的位置,之后你可以前进,问能不能到达最后一个元素位置. 比如: A = [2, 3, 1, 1, 4], return true. 一种走法是 0 - 2 - 3 - 4,还有一种走法是 0 - 1 - 4 O(n ^ 2) 解法 一个很显然,几乎不用动脑的解法. 设置一个布尔数组f,f[0] === true 表示 index === 0 这个位置能够到达,模拟每个…