A. Kefa and First Steps Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/580/problem/A Description Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) h…

580A - Kefa and First Steps 思路:dp dp[i]表示包括前i个元素中a[i]在内的最大增序列. 代码: #include<bits/stdc++.h> using namespace std; ; int a[N]; int dp[N]; int main() { ios::sync_with_stdio(false); cin.tie(); int n; cin>>n; dp[]=; ; ;i<n;i++)cin>>a[i]; ;i…

A. Kefa and First Steps time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 …

A. Kefa and First Steps time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 …

Problem description Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreas…

题目链接:http://www.codeforces.com/problemset/problem/580/A题意:求最长连续非降子序列的长度.C++代码: #include <iostream> using namespace std; ; int n, a[maxn], tmp, ans; int main() { cin >> n; ; i < n; i ++) cin >> a[i]; tmp = ans = ; ; i <= n; i++) ])…

原题连接:http://codeforces.com/contest/580/problem/A 题意: 给你一个序列,问你最长不降子串是多长? 题解: 直接模拟就好了 代码: #include<iostream> using namespace std; int n; int main() { cin.sync_with_stdio(false); cin >> n; int p; cin >> p; ) { cout << << endl;…

580A. Kefa and First Steps 题目链接: A. Kefa and First Steps 题意描述: 给出一个序列,求最长不降连续子序列多长? 解题思路: 水题,签到 代码: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; int main () { int e, s, num, n,…

水 A - Kefa and First Steps /************************************************ * Author :Running_Time * Created Time :2015/9/23 星期三 00:19:33 * File Name :A.cpp ************************************************/ #include <cstdio> #include <algorithm&…

在应用 CSS3 渐变/动画时,有个控制时间的属性 <animation-timing-function> .它的取值中除了常用到的 贝萨尔曲线以外,还有个让人比较困惑的 steps() 函数. teps(n,start/end) 第一个参数 number 为指定的间隔数,即把动画分为 n 步阶段性展示,第二个参数默认为 end,设置最后一步的状态,start 为结束时的状态,end 为开始时的状态. steps 有两个参数 第一个肯定是分几步执行完 第二个有两个值 start 第一帧是第一步…