Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 ->…

https://leetcode-cn.com/problems/delete-node-in-a-linked-list/ 非常巧妙的一道题. 题目没有给head,心想没有head我怎么才能找到要删除的值对应的节点呢? 仔细一看,题中函数的参数给的不是值,而是要删除的节点node.反而降低了解题难度: 1. 把node.next的值赋给node 2. 把node.next指向node.next.next 其实相当于删除node.next /** * Definition for singly-…

2.3 Implement an algorithm to delete a node in the middle of a singly linked list, given only access to that node.EXAMPLEInput: the node c from the linked list a->b->c->d->eResult: nothing is returned, but the new linked list looks like a- >…

题目: Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -…

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 ->…

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Given linked list -- head = [4,5,1,9], which looks like following: 4 -> 5 -> 1 -> 9 Example 1: Input: head = [4,5,1,9], node = 5 Output:…

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. Given linked list -- head = [4,5,1,9], which looks like following: Example 1: Input: head = [,,,], node = Output: [,,] Explanation: You are g…

编写一个函数,在给定单链表一个结点(非尾结点)的情况下,删除该结点. 假设该链表为1 -> 2 -> 3 -> 4 并且给定你链表中第三个值为3的节点,在调用你的函数后,该链表应变为1 -> 2 -> 4. 详见:https://leetcode.com/problems/delete-node-in-a-linked-list/description/ Java实现: /** * Definition for singly-linked list. * public cla…

题目: 删除链表中倒数第n个节点 给定一个链表,删除链表中倒数第n个节点,返回链表的头节点.  样例 给出链表1->2->3->4->5->null和 n = 2. 删除倒数第二个节点之后,这个链表将变成1->2->3->5->null. 注意 链表中的节点个数大于等于n 解题: 要删除倒数第n个节点,我们要找到其前面一个节点,也就是倒数第n+1的节点,找到这个节点就可以进行删除.和上题的思想很类似, 定义两个指针,p和cur,cur指针向前走,走了n…

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