Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;Now please try your lucky. #include<iostream> #include<math.h> #include<stdio.h> using namespace std; double deal(double x) { return…

题目链接: http://poj.org/problem?id=2109 参考: http://blog.csdn.net/code_pang/article/details/8263971 题意: 给定n,p,求k使得kn=p(1≤n≤200, 1≤p<10101, 1≤k≤109) 分析: 高精度+二分~~ k的位数为p的位数除以n的向上取整,这样知道k的位数便可以在范围内二分了~注意这里的答案是向下取整~~ 代码: #include<cstring> #include<cst…

Cable master Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 32191 Accepted: 6888 Description Inhabitants of the Wonderland have decided to hold a regional programming contest. The Judging Committee has volunteered and has promised to orga…

题意:给你n个数,要你在这n个数里面找到一些连续的数,这些数的数量大于等于m,并且他们的平均值在这n个数里面是最大的....... 思路:先把n个数的最大最小值确定,然后二分枚举平均值,对于每一个连续数,只要他们减去平均值大于0,就调制上限制,不然调整下限制,....... #include<iostream> #include<stdio.h> #include<string.h> using namespace std; double s[100005],sum[1…

http://acm.hdu.edu.cn/showproblem.php?pid=2199 给出y的值求x: 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 = Y x是0到100的实数所以要用二分的方法: #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include <algori…

https://vjudge.net/problem/CodeForces-782B B. The Meeting Place Cannot Be Changed time limit per test 5 seconds memory limit per test 256 megabytes input standard input output standard output The main road in Bytecity is a straight line from south to…

http://acm.hdu.edu.cn/howproblem.php?pid=2199 Can you solve this equation? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 13468    Accepted Submission(s): 6006 Problem Description Now,given the…

题目:洛谷P2293.BZOJ1213. 题目大意:给你$n,k(n\leq 10^{10000},k\leq 50)$,求$\lfloor \sqrt[k]{n}\rfloor$. 解题思路:高精度+二分+快速幂. 我压了九位. 这题真的卡的我丧心病狂啊!!开始无脑高精度,后来T的不知道哪去了. 首先高精度乘法中除法取模运算特别慢,要放在乘完后再处理. 还有最重要的优化:如果当前的答案的位数乘k减k+1大于n的位数,则不需要进行乘法,因为答案一定失败. 然后尽量减少传值,努力卡常即可. 可怜我…

最近写的文章好像还很多的.那么今天我们来讨论NOIP初赛的题型--完善程序.完善程序相对是比较难的题目了.全卷100分,完善程序占了大概26分,占比非常大.如果和英语考试试卷做比较,相当于首字母填空(估计是很多人的噩梦).这类题型难度很大.本文讲一下做类似题目的方法. 不过首先,需要足够的知识储备,不然再多技巧也没用. 第一步:看提示,提示往往有很大的作用. 举例:NOIP2016第一题. 完善程序: **(读入整数)**请完善下面的程序,使得程序能够读入两个 int 范围内的整数, 并将这两个…

[POJ2109]Power of Cryptography 试题描述 Current work in cryptography involves (among other things) large prime numbers and computing powers of numbers among these primes. Work in this area has resulted in the practical use of results from number theory a…