Climbing Stairs爬楼梯——动态规划】的更多相关文章

题目描写叙述: 初阶:有n层的台阶,一開始你站在第0层,每次能够爬两层或者一层. 请问爬到第n层有多少种不同的方法? 进阶:假设每次能够爬两层.和倒退一层,同一个位置不能反复走,请问爬到第n层有多少种不同的方法? 解题思路: 初阶:一维动态规划.爬楼梯数目事实上是一个斐波拉契数列. 假定f[i] 表示是爬到第i层的方法,那么f[i] = f[i-1] + f[i-2] //第i层的方法数目等于第i-1层数目加上第i-2层数目. 初值:f[0] = 1, f[1] = 1. //最開始没有爬和第一…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanation:…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanation:…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanation:…
On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…
On a staircase, the i-th step has some non-negative cost cost[i] assigned (0 indexed). Once you pay the cost, you can either climb one or two steps. You need to find minimum cost to reach the top of the floor, and you can either start from the step w…
题目描述 要爬N阶楼梯,每次你可以走一阶或者两阶,问到N阶有多少种走法 测试样例 Input: 2 Output: 2 Explanation: 到第二阶有2种走法 1. 1 步 + 1 步 2. 2 步 Input: 3 Output: 3 Explanation: 到第三阶有3种走法 1. 1 步 + 1 步 + 1 步 2. 1 步 + 2 步 3. 2 步 + 1 步 详细分析 在第0阶,可以选择走到第1阶或者第2阶,第1阶可以走第2阶或者第3阶,第二阶可以走第3阶或者第4阶....如此…
题目: You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Example 1: Input: 2 Output: 2 Explanat…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? 题意:有n阶楼梯,每次可以走一步或者两步,总共有多少种方法. 思路:动态规划.维护一个一维数组dp[n+1],dp[0]为n=0时的情况,dp[ i ]为到达第i阶台阶…
You are climbing a stair case. It takes n steps to reach to the top. Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Note: Given n will be a positive integer. Input: 2 Output: 2 Explanation: There are…