http://codeforces.com/contest/962/problem/E E. Byteland, Berland and Disputed Cities time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The cities of Byteland and Berland are located on the a…
http://codeforces.com/contest/962/problem/D D. Merge Equals time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given an array of positive integers. While there are at least two equal…
http://codeforces.com/contest/962/problem/F 求没有被两个及以上的简单环包含的边 解法:双联通求割顶,在bcc中看这是不是一个简单环,是的话把整个bcc的环加到答案中即可(正确性显然,因为bcc一定是环了,然后如果一个bcc不是简单环,那么所有边一定包含在两个简单环中) //#pragma comment(linker, "/stack:200000000") //#pragma GCC optimize("Ofast,no-stac…
C. Make a Square time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given a positive integer nn, written without leading zeroes (for example, the number 04 is incorrect). In one opera…
B. Students in Railway Carriage time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are nn consecutive seat places in a railway carriage. Each place is either empty or occupied by a pass…
A. Equator time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Polycarp has created his own training plan to prepare for the programming contests. He will train for nn days, all days are numbe…
模拟题,运用强大的stl. #include <iostream> #include <map> #include <algorithm> #include <set> #define N 150005 using namespace std; typedef long long Int; ; map<long long, set<int> > mapp; long long a[N]; int main() { int n; cin…
A. Equator(模拟) 找权值的中位数,直接模拟.. 代码写的好丑qwq.. #include<cstdio> #include<cstring> #include<algorithm> #include<cmath> using namespace std; ; inline int read() { , f = ; ; c = getchar();} + c - ', c = getchar(); return x * f; } int N; in…
C. Make a Square time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output You are given a positive integer n, written without leading zeroes (for example, the number 04 is incorrect). In one operation…
D. Merge Equals time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output You are given an array of positive integers. While there are at least two equal elements, we will perform the following operatio…
E. Byteland, Berland and Disputed Cities time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output The cities of Byteland and Berland are located on the axis Ox. In addition, on this axis there are also…
Educational Codeforces Round 65 (Rated for Div. 2)题解 题目链接 A. Telephone Number 水题,代码如下: Code #include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 2e5 + 5; int a[N] ; int n, T; char s[N] ; int main() { cin >> T; whil…
\(Educational\ Codeforces\ Round\ 85\ (Rated\ for\ Div.2)\) \(A. Level Statistics\) 每天都可能会有人玩游戏,同时一部分人会过关,玩游戏的人数和过关的人数会每天更新,问记录的数据是否没有矛盾 //#pragma GCC optimize("O3") //#pragma comment(linker, "/STACK:1024000000,1024000000") #include<…
Problem   Educational Codeforces Round 60 (Rated for Div. 2) - C. Magic Ship Time Limit: 2000 mSec Problem Description Input Output The only line should contain the minimal number of days required for the ship to reach the point (x2,y2)(x2,y2). If it…
Problem   Educational Codeforces Round 60 (Rated for Div. 2) - D. Magic Gems Time Limit: 3000 mSec Problem Description Input The input contains a single line consisting of 2 integers N and M (1≤N≤10^18, 2≤M≤100). Output Print one integer, the total n…
Educational Codeforces Round 43 (Rated for Div. 2) https://codeforces.com/contest/976 A #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define IT set<ll>::iterator #define sqr(x)…
Educational Codeforces Round 35 (Rated for Div. 2) https://codeforces.com/contest/911 A 模拟 #include<bits/stdc++.h> using namespace std; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 #define IT set<ll>::iterator #define sqr(…
Codeforces Educational Codeforces Round 44 (Rated for Div. 2) F. Isomorphic Strings 题目连接: http://codeforces.com/contest/985/problem/F Description You are given a string s of length n consisting of lowercase English letters. For two given strings s an…
Codeforces Educational Codeforces Round 44 (Rated for Div. 2) E. Pencils and Boxes 题目连接: http://codeforces.com/contest/985/problem/E Description Mishka received a gift of multicolored pencils for his birthday! Unfortunately he lives in a monochrome w…
Educational Codeforces Round 63 (Rated for Div. 2)题解 题目链接 A. Reverse a Substring 给出一个字符串,现在可以对这个字符串进行一次翻转,问是否存在一种方案,可以使得翻转后字符串的字典序可以变小.   这个很简单,贪心下就行了. 代码如下: Code #include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 3e5…
Educational Codeforces Round 39 (Rated for Div. 2) G 题意: 给一个序列\(a_i(1 <= a_i <= 10^{9}),2 <= n <= 200000\), 如果至多删除其中的一个数之后该序列为严格上升序列,那么称原序列为几乎严格上升序列. 现在每次将序列中的任意数字变成任意数字,问最少要操作几次才能将序列变成几乎严格上升子序列. 思路: 如果不考虑删除,求让整个序列都变成严格上升子序列的次数 求出\(序列a_i - i\)…
Educational Codeforces Round 48 (Rated for Div. 2) C. Vasya And The Mushrooms 题目链接:https://codeforces.com/contest/1016/problem/C 题意: emmm,说不清楚,还是直接看题目吧. 题解: 这个题人行走的方式是有一定的规律的,最后都是直接走到底,然后从另外一行走回来.并且通过画图观察,会发现他走到格子的时间会有一定的规律. 所以就维护几个前缀和就行了,从1到n枚举一下,还要…
Educational Codeforces Round 60 (Rated for Div. 2) 题目链接:https://codeforces.com/contest/1117 A. Best Subsegment 题意: 给出n个数,选取一段区间[l,r],满足(al+...+ar)/(r-l+1)最大,这里l<=r,并且满足区间长度尽可能大. 题解: 因为l可以等于r,所以我们可以直接考虑最大值,因为题目要求,直接求连续的最大值的长度就是了. 代码如下: #include <bits…
Educational Codeforces Round 59 (Rated for Div. 2) D. Compression 题目链接:https://codeforces.com/contest/1107/problem/D 题意: 给出一个n*(n/4)的矩阵,这个矩阵原本是一些01矩阵,但是现在四个四个储存进二进制里面,现在给出的矩阵为0~9以及A~F,表示0~15. 然后问这个矩阵能否压缩为一个(n/x)*(n/x)的矩阵,满足原矩阵中大小为x*x的子矩阵所有数都相等(所有子矩阵构…
Educational Codeforces Round 58 (Rated for Div. 2)  题目总链接:https://codeforces.com/contest/1101 A. Minimum Integer 题意: 多组数据,给你三个数l,r,d,要求在区间[l,r]之外找一个最小的x,使得x%d==0. 题解: 当d<l or d>r的时候,直接输出d就好了. 当l<=d<=r的时候,找到最小的t,使得t*d>r就行了. 具体操作见代码: #include…
Educational Codeforces Round 34 (Rated for Div. 2) A Hungry Student Problem 题目链接: http://codeforces.com/contest/903/problem/A 思路: 直接模拟 代码: #include <bits/stdc++.h> using namespace std; int main() { int n; scanf("%d",&n); while(n--) { i…
Educational Codeforces Round 69 (Rated for Div. 2) E. Culture Code 题目链接 题意: 给出\(n\)个俄罗斯套娃,每个套娃都有一个\(in_i,out_i\),并满足\(out_i>in_i\).定义套娃\(i\)能套在套娃\(j\)里面,当且仅当\(out_i\leq in_j\). 定义极大套娃组:当且仅当不能有另外一个套娃套在它们身上. 定义套娃组额外空间为\(in_1+(in_2-out_1)+\cdots +(in_k-…
Educational Codeforces Round 64 (Rated for Div. 2)题解 题目链接 A. Inscribed Figures 水题,但是坑了很多人.需要注意以下就是正方形.圆以及三角形的情况,它们在上面的顶点是重合的. 其余的参照样例判断一下就好了了.具体证明我也不会 代码如下: Code #include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 2e5 +…
Educational Codeforces Round 71 (Rated for Div. 2)-F. Remainder Problem-技巧分块 [Problem Description] ​ 初始\([1,500000]\)都为0,后续有两种操作: ​ \(1\).将\(a[x]\)的值加上\(y\). ​ \(2\).求所有满足\(i\ mod\ x=y\)的\(a[i]\)的和. [Solution] ​ 具体做法就是,对于前\(\sqrt{500000}=708\)个数,定义\(…
Educational Codeforces Round 71 (Rated for Div. 2)-E. XOR Guessing-交互题 [Problem Description] ​ 总共两次询问,每次询问给出\(100\)个不同的数,评测系统对于每次询问,随机从\(100\)个数中选择一个数\(a\),返回\(x\oplus a\).让你通过两次返回的值猜出\(x\)值是多少.要求两次询问的\(200\)个数互不相同,且题目保证\(x\)值固定不变. [Solution] ​ 题目要求所…