1080. Graduate Admission (30) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if yo…

1080. Graduate Admission (30) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if yo…

1080 Graduate Admission (30 分)   It is said that in 2011, there are about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each…

1080. Graduate Admission It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applica…

时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to aut…

It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province.  It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide…

It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide t…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<iostream> #include<algorithm> using namespace std;…

先对学生们进行排序,并且求出对应排名. 对于每一个学生,按照志愿的顺序: 1.如果学校名额没满,那么便被该学校录取,并且另vis[s][app[i].ranks]=1,表示学校s录取了该排名位置的学生. 2.如果该学校名额已满,那么看看vis[s][app[i].ranks]是否为1,若是,则表明学校有录取过和他排名一样的学生,那么该学生也能被录取. 否则,学生未录取. #include <iostream> #include <cstdio> #include <algor…

题意: 输入三个正整数N,M,K(N<=40000,M<=100,K<=5)分别表示学生人数,可供报考学校总数,学生可填志愿总数.接着输入一行M个正整数表示从0到M-1每所学校招生人数,N行数据分别包括两个成绩和K个志愿.输出M行依照平行志愿原则输出每所学校录取的学生序号,如果成绩相同,可以突破计划招生人数. trick: 不是很懂为什么当我输出的时候采用if(i>0)cout<<"\n";会导致测试点2和4格式错误..... 发现最后一行必须要换行…