原题:pid=688426044611322&round=344496159068801">https://www.facebook.com/hackercup/problems.php?pid=688426044611322&round=344496159068801 题意:你和一个朋友玩足球游戏,分数从0-0開始,终于你总是赢.而且你主要有两种方式赢,第一种stressFree方式你肯定要进第一个球而且总是比你的朋友分数高,另外一种stressFull方式除了你的朋友达…

原标题:https://www.facebook.com/hackercup/problems.php?pid=759650454070547&round=344496159068801 题意:给定一颗有根树,在树上下层的节点要给上层节点礼物,根节点的礼物则给慈善会,可是给礼物有个条件就是你不能送你的父节点已经送出的礼物.问满足要求的最少花费. 题解:这个题卡了一段时间,相似于染色问题,能够用树形动态规划求解.由于已知节点个数为N,则我们单个节点的最大花费不会超过log2(N) = 18. 1.…

题意:给定A,B,K(A<=B)三个数,问在[A,B]范围内的数素数因子个数为K的个数. 题解:典型的筛选法求素数.首先建立一个保存素数因子个数的数组factorNum[],以及到n为止含有素数因子个数为k的二维数组sumNum[n][k]. factorNum能够由筛选法确定.初始化数组为0. 1. 从小到大遍历给定最大范围内的数,若遍历到数n时,factorNum[n]=0则说明这个数是素数(前面没有它的因子). 2. 然后通过添加n的倍数,来筛选出最大范围内含有素数因子n的数. sumNu…

Facebook Hacker Cup 2014 Qualification Round比赛Square Detector题的解题报告.单击这里打开题目链接(国内访问需要那个,你懂的). 原题如下: Square Detector Problem Description You want to write an image detection system that is able to recognize different geometric shapes. In the first ver…

1182 完美字符串             题目来源:                         Facebook Hacker Cup选拔         基准时间限制:1 秒 空间限制:131072 KB 分值: 5         难度:1级算法题 约翰认为字符串的完美度等于它里面所有字母的完美度之和.每个字母的完美度可以由你来分配,不同字母的完美度不同,分别对应一个1-26之间的整数. 约翰不在乎字母大小写.(也就是说字母F和f)的完美度相同.给定一个字符串,输出它的最大可能的完…

VK Cup 2015 - Round 1 (unofficial online mirror, Div. 1 only)E. The Art of Dealing with ATM Time Limit: 2 Sec  Memory Limit: 256 MBSubmit: xxx  Solved: 2xx 题目连接 http://codeforces.com/contest/529/problem/E Description ATMs of a well-known bank of a sm…

2014 Qualification Round Solutions 2013年11月25日下午 1:34 ...最简单的一题又有bug...自以为是真是很厉害! 1. Square Detector (20 Points) When facing a problem in a programming contest there are three main things to consider when planning your solution. In order of importanc…

E. Correcting Mistakes Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset/problem/533/E Description Analyzing the mistakes people make while typing search queries is a complex and an interesting work. As there is no guarant…

题意: n * m的棋盘, k个位置有"rook"(车),q次询问,问是否询问的方块内是否每一行都有一个车或者每一列都有一个车? 满足一个即可 先考虑第一种情况, 第二种类似,swap一下就可以了. #include <bits/stdc++.h> using namespace std; ; inline int GetIdx(int l, int r){ return l + r | l != r; } ]; void update(int l, int r, int…

题目链接: http://codeforces.com/problemset/problem/533/B B. Work Group time limit per test2 secondsmemory limit per test256 megabytes 问题描述 One Big Software Company has n employees numbered from 1 to n. The director is assigned number 1. Every employee of…

E. Rooks and Rectangles Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset/problem/524/E Description Polycarpus has a chessboard of size n × m, where k rooks are placed. Polycarpus hasn't yet invented the rules of the game…

题目链接:http://codeforces.com/contest/533/problem/E E. Correcting Mistakes time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Analyzing the mistakes people make while typing search queries is a…

题目链接:http://codeforces.com/contest/522/problem/D 题目大意:  给你一个长度为n的序列,然后有m次查询,每次查询输入一个区间[li,lj],对于每一个查询,输出在这个区间内的两个相等的数的最短距离,如果没有相等的则输出-1. 线段树+扫描线,线段树维护的值是区间的最小值,从后往前扫,然后每次要做的事有两个: 1.判断当前这个位置 i 的数刚刚是不是出现过,假设刚刚出现的位置是 l ,如果出现过,则在线段树中把l这个位置的值更新为 l - i,同时更…

VK Cup 2012 Round 3 (Unofficial Div. 2 Edition) 代码 VK Cup 2012 Round 3 (Unofficial Div. 2 Edition) A. Problem About Equation 每个杯子体积\[V=\frac{b+\sum{a_i}}{n}\] 判断是否有\(a_i > V\). B. File List 处理出'.'的位置. 第一个'.'和最后一个'.'特判字符长度是否合法. 连续的两点位置差\(d\in[2, 11]\)…

Forethought Future Cup - Elimination Round 窝也不知道这是个啥比赛QwQ A. Love "A" 给你一个串,你可以删去若干个元素,使得最后a的个数严格大于一半.求最大串长. #include<iostream> #include<cstdio> #include<cstring> using namespace std; char s[55];int v=0,n; int main() { scanf(&q…

CF1146 Forethought Future Cup Elimination Round Tutorial 叮,守夜冠军卡 https://codeforces.com/blog/entry/66639 B 有一个串\(s\),生成了一个新串\(t=s+s'\),\(s'\)是\(s\)去掉所有'a'之后的串,给出\(t\),求\(s\) 如果只看不是'a'的数量也只有最多一个位置满足条件,直接判一下这个位置即可. https://codeforces.com/contest/1146/s…

Codeforces Round #405 (rated, Div. 2, based on VK Cup 2017 Round 1) 全场题解 菜鸡只会A+B+C,呈上题解: A. Bear and Big Brother 题意:我也没看太清,就是给你两个10以内的数a,b.a每天乘以3,b每天乘以2,求多少天后a大于b. 思路:应该是有公式的,不过看到数据这么小直接暴力乘求解.官方题解貌似就是这样,数据小就是水题. const int N=1e3+10; int main() { int a…

题目链接: http://codeforces.com/problemset/problem/522/D D. Closest Equals time limit per test3 secondsmemory limit per test256 megabytes 问题描述 You are given sequence a1, a2, ..., an and m queries lj, rj (1 ≤ lj ≤ rj ≤ n). For each query you need to print…

B. Photo to Remember Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/522/problem/B Description One day n friends met at a party, they hadn't seen each other for a long time and so they decided to make a group photo together…

D. Closest Equals Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://www.lydsy.com/JudgeOnline/problem.php?id=3224 Description You are given sequence a1, a2, ..., an and m queries lj, rj (1 ≤ lj ≤ rj ≤ n). For each query you need to print the minimu…

传送门 A. Reposts time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friend…

A. Is it rated? time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output Is it rated? Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to a…

A. Is it rated? time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Is it rated? Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to a…

B. Problems for Round 题目连接: http://www.codeforces.com/contest/673/problem/B Description There are n problems prepared for the next Codeforces round. They are arranged in ascending order by their difficulty, and no two problems have the same difficult…

地址:http://codeforces.com/contest/807/problem/D 题目: D. Dynamic Problem Scoring time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Vasya and Petya take part in a Codeforces round. The round las…

B. Problems for Round time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are n problems prepared for the next Codeforces round. They are arranged in ascending order by their difficulty,…

连接在这里,->点击<- A. Bear and Game time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and ther…

题目链接:http://codeforces.com/problemset/problem/164/A 思路:用vector分别保留原图和发图,然后分别从val值为1的点正向遍历,va值为2的点反向遍历,如果某个点这两种方式都可以遍历到,则输出1,否则输出0. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <vector>…

A - Little Artem and Presents (div2) 1 2 1 2这样加就可以了 #include <bits/stdc++.h> typedef long long ll; const int N = 1e5 + 5; int main() { int n; scanf ("%d", &n); int ans = n / 3 * 2; if (n % 3) { ans++; } printf ("%d\n", ans);…

A.暴力枚举,注意游戏最长为90分钟 B.暴力,c[l]++,c[r]--,记录中间有多长的段是大小为n的,注意特判m=0的情况 C.暴力枚举,我居然一开始没想出来!我一直以为每次都要统计最大的,就要O(N^3).实际上只要判断最大的那个. D.构造,在除了a,b,c,d之外的点构造一条链,只需要n+1条边就可以了.n=4的时候特判.…